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satela [25.4K]
3 years ago
7

DNA bases are attached to _____.

Chemistry
1 answer:
horsena [70]3 years ago
8 0

Answer:

sugar molecules......

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4HF(g)+SiO2(s)→SiF4(g)+2H2O(l)
Alecsey [184]
<span>Gallium-72 that is what i got when i did the math for it</span>
8 0
3 years ago
What is the net ionic equation of the reaction of mgso4 with sr(no3)2?
Bad White [126]

Balanced chemical reaction:  

MgSO₄(aq) + Sr(NO₃)₂(aq) → Mg(NO₃)₂(aq) + SrSO₄(s).

Ionic reaction:  

Mg²⁺(aq) + SO₄²⁻(aq) + Sr²⁺(aq) + 2NO₃⁻(aq) → Mg²⁺(aq) + 2NO₃⁻(aq) + SrSO₄(s).

Net ionic reaction:

Sr²⁺(aq) + SO₄²⁻(aq) → SrSO₄(s).

Magnesium sulfate (MgSO₄), strontium nitrate (Sr(NO₃)₂ and magnesium nitrate (Mg(NO₃)₂) are soluble in water. Strontium sulfate (SrSO₄) is not soluble in water.

This chemical reaction is double displacement reaction - cations and anions of the two reactants switch places and form two new compounds.


6 0
3 years ago
Read 2 more answers
Balance the Equation <br>with the steps please:)​
vivado [14]

Explanation:

Fe2o3+ 3co ---------. 2fe + 3co2

8 0
3 years ago
Read 2 more answers
4 Al + 3 O2 --&gt; 2 Al2O3
SIZIF [17.4K]

Answer:

The answer to your question is 7.4 moles of Aluminum

Explanation:

Data

moles of Al = ?

moles of Al₂O₃ = 3.7

Balanced chemical reaction

                4 Al  +  3 O₂  ⇒  2 Al₂O₃

To solve this problem use proportions and cross multiplication. Use the coefficients of the balanced chemical equation.

                4 moles of Aluminum ----------------- 2 moles of Al₂O₃

                 x                                  ----------------- 3.7 moles of Al₂O₃

                            x = (3.7 x 4) / 2

                            x = 14.8 / 2

                            x = 7.4 moles of Aluminum

5 0
3 years ago
Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
Leto [7]

Answer: The nuclide symbol of X is ^{231}_{90}\textrm{Th}

Explanation:

The given nuclear reaction is a type of alpha decay process. In this process, the nucleus decays by releasing an alpha particle. The mass number of the nucleus is reduced by 4 units and atomic number is also decreased by 2 units. The particle released is a helium nucleus.

The general equation representing alpha decay process is:

_{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\textrm{He}

For the given equation :

^{235}_{92}\textrm{U}\rightarrow ^{A}_{Z}\textrm{X}+^4_2\textrm{He}

As the atomic number and mass number must be equal on both sides of the nuclear equation:

^{235}_{92}\textrm{U}\rightarrow ^{231}_{90}\textrm{Th}+^4_2\textrm{He}

Thus the nuclide symbol of X is ^{231}_{90}\textrm{Th}

5 0
3 years ago
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