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Rashid [163]
3 years ago
10

How many moles of sucrose are in 5.25x1029 sucrose molecules?

Chemistry
1 answer:
Pavel [41]3 years ago
4 0

Answer:

872093.02moles

Explanation:

Given parameters:

Number of atoms of Sucrose  = 5.25 x 10²⁹atoms

Unknown:

Number of moles  = ?

Solution:

To solve this problem, we must understand that a mole of any substance contains the Avogadro's number of particles.

             6.02 x 10²³ atoms makes up 1 mole of an atom

             5.25 x 10²⁹ atoms will contain = \frac{5.25 x 10^{29} }{6.02 x 10^{23} }  = 872093.02moles

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Which phase of matter is distinguished by a superheated gas that emits light?
mariarad [96]

Answer:

I think it is Plasma

Explanation:

7 0
3 years ago
How many liters of 4.0 M NaOH solution will react with 0.60 liters 3.0 M H2SO4?
slava [35]

Answer:

A. 0.90 L.

Explanation:

  • NaOH solution will react with H₂SO₄ according to the balanced reaction:

<em>H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.</em>

<em>1.0 mole of H₂SO₄ reacts with 2.0 moles of NaOH.</em>

  • For NaOH to react completely with H₂SO₄, the no. of millimoles should be equal.

<em>∴ (MV) NaOH = (xMV) H₂SO₄.</em>

x for H₂SO₄ = 2, due to having to reproducible H⁺ ions.

<em>∴ V of NaOH = (xMV) H₂SO₄/ M of NaOH</em> = 2(0.6 L)(3.0 M)/(4.0 M) = <em>0.90 L.</em>

4 0
3 years ago
If you have 60 grams of MgCl2 in 5 liters of solution, what is the molarity of this solution?
AnnyKZ [126]

Answer:

molarity =gram/litre

=60/5

12

6 0
3 years ago
Which statements are scientific statements
Harrizon [31]
Wym there is no question or statements.
6 0
3 years ago
The density of water is 1 g/cm3. brent used the following method to convert 1 g/cm3 to kg/m3.
11111nata11111 [884]

Answer:

a) The wrong denominator for the equivalent fraction of kilograms to grams

b) The use of the scale factor of length rather than the scale factor of volume for the equivalent fraction of cubic centimeters to cubic meters

c) The arrival at the correct 1000 kg/m³ rather than 0.1 g/m³ based on the expression on the left of the equation

The density of water = 1 g/cm³

The given equation is presented as follows;

1 g/cm³ × 1 kg/(1000 kg) × 100 cm³/(1 m³) = 1000 kg/m³

The error in the conversion method are;

a) The conversion, 1 kg/(1,000 kg) has an error, the correct conversion is (1 kg)/1,000 g)

b) The volume conversion error, 100 cm³/(1 m³), the correct volume conversion is (100 cm)³/(1 m³) = 1,000,000 cm³/(1 m³)

c) The right of the equal to sign error; using the left side expression only, the (wrong) answer is 0.1 g/m³

The correct equation is presented as follows;

1 g/cm³ × 1 kg/(1000 g) × 1,000,000 cm³/(1 m³) = 1000 kg/m³

Explanation: hope this help.

7 0
2 years ago
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