Answer:
h> 2R
Explanation:
For this exercise let's use the conservation of energy relations
starting point. Before releasing the ball
Em₀ = U = m g h
Final point. In the highest part of the loop
Em_f = K + U = ½ m v² + ½ I w² + m g (2R)
where R is the radius of the curl, we are considering the ball as a point body.
I = m R²
v = w R
we substitute
Em_f = ½ m v² + ½ m R² (v/R) ² + 2 m g R
em_f = m v² + 2 m g R
Energy is conserved
Emo = Em_f
mgh = m v² + 2m g R
h = v² / g + 2R
The lowest velocity that the ball can have at the top of the loop is v> 0
h> 2R
Answer:
A
Explanation:
ignore this on...............................
Answer:
there are as many atoms in a normal breath of air as there are breathfuls of air in the atmosphere of the world
Explanation:
The answer is C. If the box is accelerating, that means that the amount of force you are exerting is greater than the force of the box.
Answer:
If one cup falls down then there will be 59 cups left.
