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AysviL [449]
3 years ago
10

A car has a mass of 1,200 kg. What is its acceleration when the engine exerts a force of 600 N? (Formula: F=ma)

Physics
1 answer:
Rasek [7]3 years ago
6 0

Answer:

Option (a)

Explanation:

Given that,

Mass of a car, m = 1200 kg

Force exerted by the engine, F = 600 N

Noe force,F = ma

a is the acceleration of the engine

a=\dfrac{F}{m}\\\\a=\dfrac{600\ N}{1200\ kg}\\\\a=0.5\ m/s^2

So, the acceleration of the car is 0.5 m/s².

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It is strong elastic and light .it is lutrous and easy to wash. so it become very popular for making clothes
Marrrta [24]

Answer:

Nylon fibres

Explanation:

Nylon fibres are synthetic polymers made of repeating units linked by amide links. It is a thermoplastic silky material which can be remoulded in any shape.

Nylon fibres have the property of strong elastic and light in weight that is why used for making ropes,  combat uniforms, and parachutes. Nylon Fibres are also lustrous and easy to wash so widely used in textile industry for making swimwear, track pants, shorts, and draperies.

Hence, the correct answer is "Nylon fibres".

6 0
3 years ago
A 93 kg zebra is traveling 13 m/s east. What is the zebra’s momentum?
Harlamova29_29 [7]
Equation: Mass x Velocity = Momentum

Answer: 93 x 13 = 1,209
3 0
3 years ago
A ball bounces on the ground. How do the ball and the ground act on each other?(1 point)
liubo4ka [24]

Answer: A is your best answer.

Explanation:

It should be A because the when the ball bounces on the ground the ground will give it force to bounce again but also it wont go as high as it first did. Hope this helps:))

3 0
3 years ago
Read 2 more answers
A metal ion (X) with a charge of 4+ is attracted to a nonmetal ion (Z) with a
Keith_Richards [23]

Answer:

A) X3Z4

Explanation:

8 0
3 years ago
A hotel elevator ascends 200m with maximum speed of 5m/s. Its acceleration and deceleration both have a magnitude of 1.0m/s2. Pa
ValentinkaMS [17]

Answer:

45 s .

Explanation:

The accelerator will first accelerate , then move with uniform velocity and at last it will decelerate to rest .

displacement s = ?

acceleration a = 1 m /s²

Final speed v = 5 m/s

initial speed u = 0

v² = u² + 2as

5² = 0 + 2 x 1 x s

s = 12.5  m

B)  Let time of acceleration or deceleration be t

v = u + a t

5 = 0 + 1 t

t = 5 s

Similarly displacement during deceleration = 12.5 m

Total distance during uniform motion = 200 - ( 12.5 + 12.5 ) =  175 m .

velocity of uniform motion = 5 m /s

time during which there was uniform velocity = 175 / 5 = 35 s

Total time = 5 + 35 + 5 = 45 s .

4 0
3 years ago
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