Answer:
The speed of the plank relative to the ice is:
![v_{p}=-0.33\: m/s](https://tex.z-dn.net/?f=v_%7Bp%7D%3D-0.33%5C%3A%20m%2Fs)
Explanation:
Here we can use momentum conservation. Do not forget it is relative to the ice.
(1)
Where:
- m(g) is the mass of the girl
- m(p) is the mass of the plank
- v(g) is the speed of the girl
- v(p) is the speed of the plank
Now, as we have relative velocities, we have:
(2)
v(g/b) is the speed of the girl relative to the plank
Solving the system of equations (1) and (2)
![45v_{g}+168v_{p}=0](https://tex.z-dn.net/?f=45v_%7Bg%7D%2B168v_%7Bp%7D%3D0)
![v_{g}-v_{p}=1.55](https://tex.z-dn.net/?f=v_%7Bg%7D-v_%7Bp%7D%3D1.55)
![v_{p}=-0.33\: m/s](https://tex.z-dn.net/?f=v_%7Bp%7D%3D-0.33%5C%3A%20m%2Fs)
I hope it helps you!
Answer:
The kilogram (kg) is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015 ×10−34 when expressed in the unit J s, which is equal to kg m2 s−1, where the meter and the second are defined in terms of c and ∆νCs.
Heat required to change the phase of ice is given by
Q = m* L
here
m = mass of ice
L = latent heat of fusion
now we have
m = 45 kg
L = 334 KJ/kg
now by using above formula
![Q = 45 * 334 * 10^3](https://tex.z-dn.net/?f=Q%20%3D%2045%20%2A%20334%20%2A%2010%5E3)
![Q = 1.5 * 10^7 J](https://tex.z-dn.net/?f=Q%20%3D%201.5%20%2A%2010%5E7%20J)
In KJ we can convert this as
![Q = 1.5 * 10^4 kJ](https://tex.z-dn.net/?f=%20Q%20%3D%201.5%20%2A%2010%5E4%20kJ)
so the correct answer is D option
O2 refers to two oxygen atoms bonded together, while 2 O refers to two oxygen atoms that are not bonded to each other. They both have two oxygen atoms, but in O2, the oxygen atoms are bonded, while in 2O, the atoms are not.
Answer:
It is C on edge.
Explanation:
Because I just figured it out and got it right and because it says so in the link provided from the question.