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Lilit [14]
3 years ago
13

What is the volume occupied by 6.56 kg of Al?

Chemistry
2 answers:
drek231 [11]3 years ago
8 0
Answer is:<span>volume occupied by 6.56 kg of Al is 2430 dm</span>³.<span>
</span>The density of aluminum is 2,7 kg/m³.
m(Al) = 6,56 kg.
V(Al) = m(Al) ÷ d(Al).
V(Al) = 6,56 kg ÷ 2,7 kg/m³.
V(Al) = 2,43 m³ = 2,43 · 1000 = 2430 dm³.
d(Al) - density of aluminium.
V(Al) - volume of aluminium.
Norma-Jean [14]3 years ago
3 0
If we are given the mass, the volume that the certain substance occupies is calculated by using the density in the equation,
 
      V = m/D

where V is the volume, mi s the mass, and D is density. From the reliable sources, the value of the density of the substance is equal to 2,700 kg/m³. 

Substituting the known values from to the equation,

     V - (6.56 kg)/(2700 kg/m³)
      V = 2.429 x 10^-3 m³

Answer: 2.429 x 10^-3 m³

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