Question

What is the volume occupied by 6.56 kg of Al?

Answer 1

Answer is:volume occupied by 6.56 kg of Al is 2430 dm³.
The density of aluminum is 2,7 kg/m³.
m(Al) = 6,56 kg.
V(Al) = m(Al) ÷ d(Al).
V(Al) = 6,56 kg ÷ 2,7 kg/m³.
V(Al) = 2,43 m³ = 2,43 · 1000 = 2430 dm³.
d(Al) - density of aluminium.
V(Al) - volume of aluminium.

Answer 2

If we are given the mass, the volume that the certain substance occupies is calculated by using the density in the equation,
 
      V = m/D

where V is the volume, mi s the mass, and D is density. From the reliable sources, the value of the density of the substance is equal to 2,700 kg/m³. 

Substituting the known values from to the equation,

     V - (6.56 kg)/(2700 kg/m³)
      V = 2.429 x 10^-3 m³

Answer: 2.429 x 10^-3 m³