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Korvikt [17]
3 years ago
14

PLEASE HELP WILL MARK BRAINLIEST

Physics
1 answer:
aniked [119]3 years ago
6 0
2kg objects in the world of a hunting group
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If a radioactive decay produced 2. 05 × 1011 j of energy, how much mass was lost in the reaction?
Morgarella [4.7K]

The mass lost in the reaction is 0.227 × 10^{-5} Kg

The energy that is released during a nuclear reaction can be related to the mass lost using the Einstein equation.

E = mc^{2} by Einstein demonstrates that matter and energy are only two different manifestations of the same thing. It also demonstrates how much energy (E) can fit into a relatively small mass (m) of matter. Nuclear processes convert matter into energy, yet the combined amount of mass and energy remains constant.

Given that;

E = Δmc^{2}

Δm = \frac{ E}{c^{2} }

Δm =  2. 05 × 10^11  J/( 3 × 10^8)^2

Δm = 0.227 × 10^{-5} Kg

Learn more about Einstein's equation:

brainly.com/question/10809666

#SPJ4

6 0
2 years ago
Can cars stop on a dime? Calculate the acceleration of a 1400 kg car if it can stop from 35 km/h on a dime (diameter= 1.7 cm) ho
Deffense [45]

Answer:

The acceleration of the cart is 283.54g

Explanation:

It is given that,

Initial speed of the car, u = 35 km/h = 9.72 m/s

Finally, it stops, v = 0

Diameter of the dime, d = 1.7 cm

Let a is the acceleration of the car. Using third equation of motion to find it as :

v^2-u^2=2ad

-u^2=2ad

a=\dfrac{-u^2}{2d}

a=-\dfrac{(9.72)^2}{2\times 1.7\times 10^{-2}}

a=-2778.77\ m/s^2

So, the acceleration of the car is 2778.77\ m/s^2 and it is decelerating.

Since, g=9.8\ m/s^2

So, a=\dfrac{2778.77}{9.8}=283.54\ g

So, the acceleration of the cart is 283.54g. Hence, this is the required solution.

6 0
3 years ago
In each of the given pairs, choose which element will have the bigger atom. Give reasons for your choice. (a) Mg (atomic number
Dafna1 [17]

Answer:

Mg (atomic number 12)

K (atomic number 19)

Explanation:

The size of an atom is estimated in terms of its atomic radius.

The atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance (d) between two nuclei in the solid - state of metals.

  • Across a period, atomic radii decrease progressively from left to right.
  • This is due to the progressive increase in the nuclear charge without increase in the number of electronic shells.
  • Down a group, atomic radii increase progressively due to the successive shells of electrons being added which have been compensated for by the increase in nuclear charge.

Cl is further right of Mg in the third period

K is below Na in the first group

3 0
3 years ago
A fighter-bomber is making a bombing run flying horizontally at 500 knots (100 m/s). At an altitude of 100 m. a. How long will i
DanielleElmas [232]

Answer:

5\:\mathrm {s}

Explanation:

We can use kinematics equation \Delta y={v_i}t+\frac{1}{2}at^2 to solve this problem. Since v_i in the vertical direction is 0, we have:

\Delta y =\frac{1}{2}at^2 (freefall equation)

Plugging in values, we get:

100=\frac{1}{2}\cdot 9.81\cdot t^2,\\\\t^2=\frac{100}{\frac{1}{2}\cdot 9.81},\\\\t=\sqrt{20.387}\\\\t=4.515\approx \fbox{$5\:\mathrm{seconds}$}(one significant figure).

*The horizontal velocity is irrelevant in this question. It only affects the horizontal displacement of the object (where the object lands), not how long it takes for the object to hit the ground.

8 0
3 years ago
1.The lunch lady pushes a 100 kg zombie with 300 N of force. How much is the zombie accelerated?
Molodets [167]

Answer:

1. A=3.00m/s  2.m=50kg

Explanation:

1. Use the formula a=f/m

a=300/100

a=3

2.Use the formula m=f/a

m=1000/20

m=50kg

5 0
3 years ago
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