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myrzilka [38]
3 years ago
7

Coucouu besoin daide svp :)) merci davance☺​

Chemistry
1 answer:
kondaur [170]3 years ago
5 0

Answer:

hmmmmmmm what? 2 + 2 = 22 :)

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Metals react with oxygen to give oxides with the general formula MxOy. What is a balanced chemical equation for the reaction of
katovenus [111]

Answer: 4Fe+3O_2\rightarrow 2Fe_2O_3

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

Here iron is having an oxidation state of +3 called as Fe^{3+} cation and oxide O^{2-} is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Fe_2O_3.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2Fe+3O_2\rightarrow 2Fe_2O_3

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The left side of a chemical reaction is shown.
siniylev [52]

The type of chemical reaction that the reactants will undergo would be a single displacement reaction.

In a single displacement reaction, one element gets substituted or replaced by another element in a compound. This often leads to the formation of a new compound (aqueous) and a new element (solid or precipitate).

Thus, the complete equation of the reaction becomes:

             Cu + 2AgNO_3 ---> Cu (NO_3)_2 + 2Ag

Cu displaced Ag from AgNO3. Thus Ag becomes precipitated in solution while a new compound, CU(NO3)2 is formed.

More on displacement reactions can be found here: brainly.com/question/13219117

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5.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the
cupoosta [38]

Answer: Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

Explanation:

To calculate the entalpy, we use the equation:

q=mc\Delta T

where,

q = heat absorbed by water = ?

m = mass of water = {\text {volume of water}}\times {\text {density of water}}=100.0ml\times 1.00g/ml=100.0g

c = heat capacity of water = 4.186 J/g°C

\Delta T= change in temperature = 6.70^0C

q=100.0g\times 4.184J/g^0C\times 6.70^0C=2803.3J=2.8033kJ

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

The heat absorbed by water will be equal to heat released by MgSO_4

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 5.11 g

Molar mass  = 120 g/mol

Putting values in above equation, we get:

\text{Moles of }MgSO_4=\frac{5.11g}{120g/mol}=0.042mol

0.042 moles of MgSO_4 releases = 2.8033 kJ

1 mole of MgSO_4 releases = \frac{2.8033 kJ}{0.042}\times 1=66.7kJ

Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

3 0
3 years ago
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