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2 years ago

What type of precipitation occurs when the temperature of the sky is above freezing? Below

Chemistry

2 answers:

Shkiper50 [21]2 years ago

6 0

Answer:

Above freezing :- rain

Below freezing :- hail

Damm [24]2 years ago

6 0

Answer:

below freezing

Explanation:

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Min : sec helium and nickel are classified as _____, which are pure substances that make up all kinds of matter

Sidana [21]

Helium which has a chemical formula of He is considered as a noble gas while Nickel which has a chemical formula of Ni is considered as metallic. Although both have different phases but they are both classified under the general category of “Elements”.

answer:

elements

4 0

3 years ago

Create a sentence about a cat for each type of figurative language

meriva

1.) Onomatopoeia - The use of words whose sounds suggest their meanings.

Meow purred the cat as I scratched behind it's ear.

2.) Personification - A figure of speech in which human qualities are attributed to an object, animal or idea.

The cat rolled it's eyes at it's humans obnoxious behaviour.

3.) Alliteration - The repetition of sounds/letters at the beginning of a word.

The keeper couldn’t keep all the cats in their cages.

4.) Pun - A play on words.

You have cat to be kitten me right now!

5.) Hyperbole - An over-exaggeration.

The cat jumped so high I swore it was going to the moon!

6.) Idiom - A figurative meaning of the connotation of the word. (Different from the literal meaning.)

Well, she sure is another breed of cat, I'll tell you that!

(omg it rhymes too how exciting !!)

7.) Simile - A comparison using like or as.

The cat's fur was as dark as night.

8.) Metaphor - A comparison not using like or as.

The cat's fur was a blanket of warmth!!

Hope these examples helped !! :-)

5 0

3 years ago

Read 2 more answers

How much heat is needed to raise the temperature of 55.0 g sample of water by 65.0 oC.

sveticcg [70]

Answer: 14943.5 J

Explanation:

The quantity of heat energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that,

Q = ?

Mass of water = 55.0g

C = 4.18 J/g°C

Φ = 65.0°C

Then, Q = MCΦ

Q = 55.0g x 4.18 J/g°C x 65.0°C

Q = 14943.5 J

Thus, 14943.5 joules of heat is needed to raise the temperature of water.

3 0

3 years ago

Read 2 more answers

Balancing chemical equations

kolbaska11 [484]

Answer:

2B2 + 3O2 → 2B2O3

Explanation:

Balance The Equation: B2 + O2 = B2O3

1. Label Each Compound With a Variable

aB2 + bO2 = cB2O3

2. Create a System of Equations, One Per Element

B: 2a + 0b = 2c

O: 0a + 2b = 3c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

a = 2

b = 3

c = 2

4. Substitute Coefficients and Verify Result

2B2 + 3O2 = 2B2O3

L R

B: 4 4 ✔️

O: 6 6 ✔️

hope this helps!

7 0

2 years ago

In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to

labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of $NH_3$ = 100 g

Molar mass of $NH_3$ = 27 g/mole

Molar mass of $N_2$ = 28 g/mole

First we have to calculate moles of $NH_3$ .

$\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles$

The given balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the given reaction, we conclude that

2 moles of $NH_3$ produced from 1 mole of $N_2$

3.7 moles of $NH_3$ produced from $\frac{1mole}{2mole}\times 3.7mole=1.85moles$ of $N_2$

Now we have to calculate the mass of $N_2$ .

Mass of $N_2$ = Moles of $N_2$ × Molar mass of $N_2$

Mass of $N_2$ = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

5 0

3 years ago