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Scilla [17]
2 years ago
12

What type of precipitation occurs when the temperature of the sky is above freezing? Below

Chemistry
2 answers:
Shkiper50 [21]2 years ago
6 0

Answer:

Above freezing :- rain

Below freezing :- hail

Damm [24]2 years ago
6 0

Answer:

below freezing

Explanation:

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Min : sec helium and nickel are classified as _____, which are pure substances that make up all kinds of matter
Sidana [21]

Helium which has a chemical formula of He is considered as a noble gas while Nickel which has a chemical formula of Ni is considered as metallic. Although both have different phases but they are both classified under the general category of “Elements”.

 

answer:

<span>elements</span>

4 0
3 years ago
Create a sentence about a cat for each type of figurative language
meriva
1.) Onomatopoeia - <span>The use of words whose sounds suggest their meanings.

Meow purred the cat as I scratched behind it's ear.


2.) Personification - </span><span>A figure of speech in which human qualities are attributed to an object, animal or idea.
</span><span>
The cat rolled it's eyes at it's humans obnoxious behaviour.


3.) Alliteration - </span><span>The repetition of sounds/letters at the beginning of a word.

</span>The keeper c<span>ouldn’t </span>k<span>eep all the cats in their cages.
</span><span>
4.) Pun - A play on words.

You have cat to be kitten me right now!

5.) Hyperbole - An over-exaggeration.

The cat jumped so high I swore it was going to the moon!

6.) Idiom - </span><span>A figurative meaning of the connotation of the word. (Different from the literal meaning.)
</span><span>
Well, she sure is another breed of cat, I'll tell you that!

(omg it rhymes too how exciting !!)

7.) Simile - </span><span>A comparison using like or as.
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The cat's fur was as dark as night.

8.) Metaphor - </span><span>A comparison not using like or as.
</span><span>
The cat's fur was a blanket of warmth!!

Hope these examples helped !! :-)


</span>
5 0
3 years ago
Read 2 more answers
How much heat is needed to raise the temperature of 55.0 g sample of water by 65.0 oC.
sveticcg [70]

Answer: 14943.5 J

Explanation:

The quantity of heat energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that,

Q = ?

Mass of water = 55.0g

C = 4.18 J/g°C

Φ = 65.0°C

Then, Q = MCΦ

Q = 55.0g x 4.18 J/g°C x 65.0°C

Q = 14943.5 J

Thus, 14943.5 joules of heat is needed to raise the temperature of water.

3 0
3 years ago
Read 2 more answers
Balancing chemical equations
kolbaska11 [484]

Answer:

2B2 + 3O2 → 2B2O3

Explanation:

Balance The Equation: B2 + O2 = B2O3

1. Label Each Compound With a Variable

  aB2 + bO2 = cB2O3

2. Create a System of Equations, One Per Element

  B: 2a + 0b = 2c

  O: 0a + 2b = 3c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 2

  b = 3

  c = 2

4. Substitute Coefficients and Verify Result

  2B2 + 3O2 = 2B2O3

      L R

  B: 4 4 ✔️

  O: 6 6 ✔️

hope this helps!

7 0
2 years ago
In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to
labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of NH_3 = 100 g

Molar mass of NH_3 = 27 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate moles of NH_3.

\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles

The given balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the given reaction, we conclude that

2 moles of NH_3 produced from 1 mole of N_2

3.7 moles of NH_3 produced from \frac{1mole}{2mole}\times 3.7mole=1.85moles of N_2

Now we have to calculate the mass of N_2.

Mass of N_2 = Moles of N_2 × Molar mass of N_2

Mass of N_2 = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

5 0
3 years ago
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