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kaheart [24]
3 years ago
7

Two positive charges are placed near each other what happens between the charges

Physics
2 answers:
Musya8 [376]3 years ago
6 0

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Answer: coll

Explanation:

Thepotemich [5.8K]3 years ago
4 0
Answer: B
explanation: just trust❤️
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Suspensions are a homogeneous mix True False​
nirvana33 [79]

Answer:

FALSE

Explanation:

Suspensions are heterogeneous mixtures from which some of the particles settle with time.

4 0
3 years ago
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A bullet B of mass mB traveling with a speed v0 = 1400 m/s ricochets off a fixed steel plate A of mass mA. Let mA ≫ mB so that i
Greeley [361]

Answer:

Rebounce angle is 345°

Rebounce speed is 989.95m/s

Explanation:

Calculate the x  component of the velocity of the bullet before impact by using the following relation:

Vbx= Vb Cos thetha

Here,  is the initial velocity of the bullet, Vo = 1400m/s and is the incidence angle of the bullet.= theta = 15°

Substituting

Vbx = Cos15 ×1400 = 1352.30m/s

Calculate the y component using the relation:

Vby = Vo Sin theta

Vby = sin 15° × 1400

Vby = 362.35m/s

The rebounce angle = 360 - incidence angle

Rebounce angle =( 360 - 15)° = 345°

The rebound speed V' = Vby - Vbx

V' = (1352.30 - 362.35)m/s

V' = 989.95 m/s

5 0
3 years ago
What are solar flares
Bad White [126]
It's a brief of intense high energy radiation from the sun's surface. When it happens it disrupts the earth's communication and power line transmissions
8 0
3 years ago
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A surface receiving sound is moved from its original position to a position three times farther away from the source of the soun
777dan777 [17]
Intensity, E follows inverse square law.

E α  1/r²

r is the distance.

So if the distance r is increased by 3, the intensity would be reduced by 3²

3² = 9

So the answer is nines times as low.  C. 
3 0
3 years ago
Quadrupling the power output from a speaker emitting a single frequency will result in what increase in loudness (in units of dB
Leviafan [203]

Answer:

<em>6.02 dB increase  </em>

<em></em>

Explanation:

Let us take the initial power from the speaker P' = P Watt

then, the final power P = 4P Watt

for a given unit area, initial intensity (power per unit area) will be

I' = P Watt/m^2

and the final quadrupled sound will produce a sound intensity of

I = 4P Watt/m^2

Increase in loudness is gotten from the relation

ΔL =  10log_{10} \frac{I}{I'}

where

I = final sound intensity

I' = initial sound intensity

imputing values of the intensity into the equation, we have

==>  10log_{10} \frac{4P}{P} =  10log_{10} 4 = <em>6.02 dB increase  </em>

6 0
3 years ago
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