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Kobotan [32]
3 years ago
11

Convert 25 cm to km using the method of dimensional analysis

Physics
2 answers:
pogonyaev3 years ago
7 0

25 x 10^-5
= 0.00025

25 cm
= 0.00025 km
liraira [26]3 years ago
3 0

Answer:

0.00025km

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When rocks experience high temperatures and differential stresses deep in the earth, their grains tend to ________?
pochemuha
Break into small particles. The heat causes the rock to break up and form pebbles or sand. Hope that helped. Have a nice day
4 0
3 years ago
An object is thrown upward from the top of a 144​-foot building with an initial velocity of 128 feet per second. The height h of
ankoles [38]

Answer:

After 9 seconds the object reaches ground.

Step-by-step explanation:

We equation of motion given as h = -16t²+128t+144,

We need to find in how many seconds will the object hit the ground,

That is we need to find time when h = 0

                        0 = -16t²+128t+144

                       16t²-128t-144= 0

                       t=\frac{-(-128)\pm \sqrt{(-128)^2-4\times 16\times (-144)}}{2\times 16}\\\\t=\frac{128\pm \sqrt{25600}}{32}\\\\t=\frac{128\pm 160}{32}\\\\t=9s\texttt{ or }t=-1s

Negative time is not possible, hence after 9 seconds the object reaches ground.

8 0
3 years ago
Kinetic energy is the energy of . It increases with and .Potential energy is the energy of or . It increases with , and
lorasvet [3.4K]

Answer:

k is the energy of motion it increase with four of load you carry

8 0
3 years ago
A spherical balloon with radius r inches has volume V(r) = 4 3 πr3. Find an expression that represents the amount of air require
DerKrebs [107]
So the question ask to formulate an expression to represent the amount of air required to inflate the balloon from a radius of R+4 and the expression would be V=16pi/3*(3r^2+12r+16). I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarifications
4 0
3 years ago
Two cars are moving towards each other and sound emitted by first car with real frequency of 3000 hertz is detected by a person
sertanlavr [38]

Answer:

 v ’= 21.44 m / s

Explanation:

This is a doppler effect exercise that changes the frequency of the sound due to the relative movement of the source and the observer, the expression that describes the phenomenon for body approaching s

           f ’= f (v + v₀) / (v-v_{s})

where it goes is the speed of sound 343 m / s, v_{s} the speed of the source v or the speed of the observer

in this exercise both the source and the observer are moving, we will assume that both have the same speed,

                v₀ = v_{s} = v ’

we substitute

               f ’= f (v + v’) / (v - v ’)

               f ’/ f (v-v’) = v + v ’

               v (f ’/ f -1) = v’ (1 + f ’/ f)

               v ’= (f’ / f-1) / (1 + f ’/ f) v

               v ’= (f’-f) / (f + f’) v

let's calculate

                v ’= (3400 -3000) / (3000 +3400) 343

                v ’= 400/6400 343

                v ’= 21.44 m / s

3 0
2 years ago
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