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aliina [53]
3 years ago
12

What would be the consequences if the animated structures suddenly become non-polar

Physics
1 answer:
gogolik [260]3 years ago
5 0

Answer:

the lipid bilayer would not be able to hold its shape in water and the cell membrane would disassemble. Only a lipid monolayer would be possible. The fatty acid "tails' would fall off The phospholipids would flip upside down.

Explanation:

hope this helps

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When you strike two tuning forks simultaneously, you hear three beats per second. The frequency of the first tuning fork is 440
tekilochka [14]

Answer:4

Explanation:

Given

Frequency of beats is 3 beats per second

Frequency of first tuning fork is f_1=440\ Hz

Beat frequency is difference in the frequency of tuning forks i.e.

either f_1-f_2 or f_2-f_1 =3

so f_2=3+440=443\ Hz

or

f_2=440-3=437\ Hz

so there is not enough information given to decide.

5 0
3 years ago
Read 2 more answers
A photon has an energy of 5.53 à 10¯17 j. what is its frequency in s¯1?
Butoxors [25]
<span>energy is directly proportional fo frequency 
as in blue photons are more energetic than red photons 
so 
E = h * f 
look up h (Planck's constant) 
plug and play!</span><span>
</span>
5 0
3 years ago
If your phone needs to be on a charger for three hours to be fully charged, and the charger draws 2 amps, then how many electron
solong [7]

Answer:

Yes you can. The charging current will be the lowest of the two current ratings of device and charger. The charger and the phone have complex internal circuitry that enable this behaviour.

But using a weaker charger for your phone will only lengthen charging time. And using a stronger charger than that the phone will accept doesn't affect charging at all and only wastes money.

7 0
2 years ago
As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p
Irina-Kira [14]

Answer:

The magnitude of each force is 2.45 x 10⁻¹⁶ N

Explanation:

The charge of proton, +q = 1.603 x 10⁻¹⁹ C

The charge of electron, -q = 1.603 x 10⁻¹⁹ C

Distance between the two charges, r = 971 nm = 971 x 10⁻⁹ m

Apply Coulomb's law;

F = \frac{kq_1q_2}{r^2}

where;

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

q₁ and q₂ are the charges of proton and electron respectively

F is the magnitude of force between them

Substitute in the given values and solve for F

F = \frac{(8.99*10^9)(1.603*10^{-19})^2}{(971*10^{-9})^2} \\\\F = 2.45*10^{-16} \ N

Therefore, the magnitude of each force is 2.45 x 10⁻¹⁶ N

4 0
3 years ago
If the magnets are brought close together, they will
murzikaleks [220]

It depends on which side. Opposites attract, so north and south would attract to each other and collide, while north and north or south and south would go away from eachother.

7 0
3 years ago
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