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Sladkaya [172]
3 years ago
15

A diffraction grating with 210 lines per mm is used in an experiment to study the visible spectrum of a gas discharge tube. At w

hat angle from the beam axis will the first order peak occur if the tube emits light with wavelength of 506.0 nm
Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

Explanation:

Width of slit a = 1 x 10⁻³ / 210

a = 4.76 x 10⁻⁶ m .

angle at which first order peak is formed

= λ / a         (where λ is wavelength and a is width of slit)

given λ = 506 x 10⁻⁹ m

a = 4.76 x 10⁻⁶

θ = 506 x 10⁻⁹ / 4.76 x 10⁻⁶

= 106.3 x 10⁻³ radian .

first order peak is formed  at an angle of 106.3 x 10⁻³ radian .

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Explanation:

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3 years ago
What element from the periodic table produces blue color in fireworks
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3 years ago
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An object with a mass of m = 3.85 kg is suspended at rest between the ceiling and the floor by two thin vertical ropes.
Aleksandr-060686 [28]

The tension in the upper rope is determined as 50.53 N.

<h3>Tension in the upper rope</h3>

The tension in the upper rope is calculated as follows;

T(u) = T(d)+ mg

where;

  • T(u) is tension in upper rope
  • T(d) is tension in lower rope

T(u) = 12.8 N + 3.85(9.8)

T(u) = 50.53 N

Thus, the tension in the upper rope is determined as 50.53 N.

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6 0
2 years ago
The stopwatch used by a student to measure velocity of a pulse in a slinky was of least count 0.1 second. He stops the stopwatch
sweet-ann [11.9K]

Least count of the pulse stopwatch is given by

\Delta t = 0.1 s

this means each division of the stopwatch will measure 0.1 s of time

After 3 journeys from one end to other we can see that total time that is measured here is shown by the clock as 52nd division

So here total time is given as

Time = (Number of division) (Least count)

now we will have

T = 52 \times 0.1s

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4 0
3 years ago
Power selection feature for resistors to become water modules 10 liters of water at 25°C to đến
Mila [183]

Answer:

P = 2439.5 W = 2.439 KW

Explanation:

First, we will find the mass of the water:

Mass = (Density)(Volume)

Mass = m = (1 kg/L)(10 L)

m = 10 kg

Now, we will find the energy required to heat the water between given temperature limits:

E = mCΔT

where,

E = energy = ?

C = specific heat capacity of water = 4182 J/kg.°C

ΔT = change in temperature = 95°C - 25°C = 70°C

Therefore,

E = (10 kg)(4182 J/kg.°C)(70°C)

E = 2.927 x 10⁶ J

Now, the power required will be:

Power = P = \frac{E}{t}

where,

t = time = (20 min)(60 s/1 min) = 1200 s

Therefore,

P = \frac{2.927\ x\ 10^6\ J}{1200\ s}

<u>P = 2439.5 W = 2.439 KW</u>

7 0
2 years ago
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