The Kelvin scale has no negatives on it.
Zero Kelvin is 'Absolute Zero', and nothing can get colder than that.
The Answer is:
O 3s
Hope you got it right.
Given data;
Fn = 10 N
Fs = 7 N
Fe = 4 N
force in X direction (Fx) = 4 N
force in Y direction (Fy) = 10-7 = 3 N
Net force (Fnet) = Sq.root[(Fx)² + (Fy)²]
= Sq root [ 4² + 3² ]
= 25 N
<em> Net force acting = 25 N</em>