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Natali5045456 [20]
3 years ago
13

Base your answer to the question on the information below.A go-cart travels around a flat, horizontal, circular track with a rad

ius of 25 meters. The mass of the go-cart with the rider is 200. kilograms. The magnitude of the maximum centripetal force exerted by the track on the go-cart is 1200. newtons.Which change would increase the maximum speed at which the go-cart could travel without sliding off this track?
Physics
1 answer:
lakkis [162]3 years ago
4 0

Explanation:

It is given that,

Radius of the circular track, r = 25 m

Mass of the go cart with the rider, m = 200 kg

The magnitude of the maximum centripetal force exerted by the track on the go-cart is 1200 N.

The centripetal force exerted by the track o the go cart is given by :

F=\dfrac{mv^2}{r}

v is the maximum speed at which the go-cart could travel without sliding off this track.

v=\sqrt{\dfrac{Fr}{m}}

The maximum speed is directly proportional to the force and radius of track. On increasing force and radius and decreasing the mass would increase maximum speed. It is given by :

v=\sqrt{\dfrac{1200\times 25}{200}}

v = 12.24 m/s

Hence, this is the required solution.

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The wavelength is related to the frequency by the relationship:
\lambda= \frac{v}{f}
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The speed of sound in air is v=344 m/s. The lowest frequency is f=20.0 Hz, so the corresponding wavelength is
\lambda_1 =  \frac{v}{f_1}= \frac{344 m/s}{20.0 Hz}=17.2 m
The highest frequency is f_2 = 2.00 \cdot 10^4 Hz, so the corresponding wavelength is
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Therefore, the range of wavelengths of audible sound in air is
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3 years ago
Why smartphone and computer are called modern technology?​
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Answer:

Hey

I am sure from what i know that your answer should be the following:

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What is the relationship between karst development and topography?
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A horizontal beam of electrons initially moving at 4.0×10^7 m/s is deflected vertically by the vertical electric field between o
givi [52]

Answer:

1.77\times 10^{-7}\ C/m^2

0.000439077936334 m

Explanation:

q = Charge of electron = 1.6\times 10^{-19}\ C

E = Electric field = 2\times 10^{4}\ N/C

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

d = Distance between plates = 2 cm (assumed)

m = Mass of electron = 9.11\times 10^{-31}\ kg

The beam consists of electrons which means it has negative charge this means the upper plates will be positive and the lower plate will be negative.

The direction is upper to lower lower plate.

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

Electric flux is given by

\phi=\epsilon_0E\\\Rightarrow \phi=8.85\times 10^{-12}\times 2\times 10^{4}\\\Rightarrow \phi=1.77\times 10^{-7}\ C/m^2

The charge per unit area on the plates is 1.77\times 10^{-7}\ C/m^2

Deflection is given by

s=\dfrac{1}{2}\dfrac{qE}{m}(\dfrac{d}{v})^2\\\Rightarrow s=\dfrac{1}{2}\dfrac{1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}(\dfrac{0.02}{4\times 10^7})^2\\\Rightarrow s=0.000439077936334\ m

The deflection is 0.000439077936334 m

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Nicotinic acetylcholine receptor are activated through the binding of acetylcholine at the neuromuscular junction. This action leads to influx of sodium ions to accomplish endplate potential.

7 0
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