Explanation:
It is given that,
Radius of the circular track, r = 25 m
Mass of the go cart with the rider, m = 200 kg
The magnitude of the maximum centripetal force exerted by the track on the go-cart is 1200 N.
The centripetal force exerted by the track o the go cart is given by :
v is the maximum speed at which the go-cart could travel without sliding off this track.
The maximum speed is directly proportional to the force and radius of track. On increasing force and radius and decreasing the mass would increase maximum speed. It is given by :
v = 12.24 m/s
Hence, this is the required solution.
Given that,
Mass of trackler, m₁ = 100 kg
Speed of trackler, u₁ = 2.6 m/s
Mass of halfback, m₂ = 92 kg
Speed of halfback, u₂ = -5 m/s (direction is opposite)
To find,
Mutual speed immediately after the collision.
Solution,
The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :
So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.
Answer:
Explanation:
<u>Diagonal Launch </u>
It's referred to as a situation where an object is thrown in free air forming an angle with the horizontal. The object then describes a known path called a parabola, where there are x and y components of the speed, displacement, and acceleration.
The object will eventually reach its maximum height (apex) and then it will return to the height from which it was launched. The equation for the height at any time t is
Where vo is the magnitude of the initial velocity, is the angle, t is the time and g is the acceleration of gravity
The maximum height the object can reach can be computed as
There are two times where the value of y is when t=0 (at launching time) and when it goes back to the same level. We need to find that time t by making
Removing and dividing by t (t different of zero)
Then we find the total flight as
We can easily note the total time (hang time) is twice the maximum (apex) time, so the required time is