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Natali5045456 [20]
3 years ago
13

Base your answer to the question on the information below.A go-cart travels around a flat, horizontal, circular track with a rad

ius of 25 meters. The mass of the go-cart with the rider is 200. kilograms. The magnitude of the maximum centripetal force exerted by the track on the go-cart is 1200. newtons.Which change would increase the maximum speed at which the go-cart could travel without sliding off this track?
Physics
1 answer:
lakkis [162]3 years ago
4 0

Explanation:

It is given that,

Radius of the circular track, r = 25 m

Mass of the go cart with the rider, m = 200 kg

The magnitude of the maximum centripetal force exerted by the track on the go-cart is 1200 N.

The centripetal force exerted by the track o the go cart is given by :

F=\dfrac{mv^2}{r}

v is the maximum speed at which the go-cart could travel without sliding off this track.

v=\sqrt{\dfrac{Fr}{m}}

The maximum speed is directly proportional to the force and radius of track. On increasing force and radius and decreasing the mass would increase maximum speed. It is given by :

v=\sqrt{\dfrac{1200\times 25}{200}}

v = 12.24 m/s

Hence, this is the required solution.

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Alex Ar [27]

Density = mass/ volume (so here this is how you would solve the problem)

<span>D = 38.6 g/ 2 cm3 (first step)</span>

<span>D= 19.3 g/cm3  ( Do math and then you would get this)</span>

<span>
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6 0
3 years ago
1) Little Timmy wants to measure how tall his house is. He doesn’t have a tape measure but does have a stopwatch. He recruits Bi
kifflom [539]

1) 13.7 m

The motion of the rock is a free fall, with constant acceleration g=9.8 m/s^2 towards the ground, so the total distance it covers is given by the SUVAT equation:

S=\frac{1}{2}gt^2

where S is the height of the house, and t is the time the rock takes to reach the ground. Substituting t=1.67 s, we find:

S=\frac{1}{2}(9.8 m/s^2)(1.67 s)^2=13.7 m

2) 105.5 m

The motion of the stuffed chicken is a projectile motion, with a uniform horizontal motion (with constant velocity of v=36.0 m/s) and a vertical accelerated motion (with constant acceleration of g=9.8 m/s^2).

First of all, we can find the total time of the ball by considering the vertical motion only. We know the vertical distance covered, S=42.2 m, so the time of the fall is

S=\frac{1}{2}gt^2\\t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(42.2 m)}{9.8 m/s^2}}=2.93 s

And now we can consider the horizontal motion to find the horizontal distance covered by the stuffed chicken:

d=vt=(36.0 m/s)(2.93 s)=105.5 m

3) 49.4 m

Again, the motion of the ball is a projectile motion, with a horizontal motion and a vertical motion.

The range of a projectile launched from the ground can be found by using the formula:

d=\frac{v^2}{g} sin 2 \theta

where, in this case:

v = 22.0 m/s is the initial velocity

\theta=45^{\circ}

Substituting into the formula, we find

d=\frac{(22.0 m/s)^2}{9.8 m/s^2}(sin (2\cdot 45^{\circ}))=49.4 m

4) 9.6 m/s^2

The frictional force acting on the monkey is given by:

F_f = \mu mg=(0.16)(31.0 kg)(9.8 m/s^2)=48.6 N

where \mu is the coefficient of friction and m is the mass of the monkey.

We have two forces acting on the monkey: the push of F=345 N and the frictional force acting in the opposite direction. According to Newton's second law, the net force will be equal to the product between the monkey's mass and its acceleration, so we can find the acceleration:

F-F_f=ma\\a=\frac{F-F_f}{m}=\frac{345 N-48.6 N}{31.0 kg}=9.6 m/s^2

5) 462.3 N

The horizontal component of the pushing force is:

F_x = F cos \theta = (648 N)(cos 25^{\circ})=587.3 N

The frictional force, acting in the opposite direction, is

F_f = \mu mg=(0.17)(75.0 kg)(9.8 m/s^2)=125.0 N

where \mu is the coefficient of friction and m is the mass of the box.

The net force on the box is therefore given by the net force on the horizontal direction:

F_{net}=F_x -F_f=587.3 N -125.0 N=462.3 N

6) 89.5 N

First of all we need to calculate the total weight of the table and the items above it.

The weight of the table is:

W=mg=(25.0 kg)(9.8 m/s^2)=245 N

So the total weight of the table and the items is

W=245 N+63 N+12 N+44 N+24 N+9N+10N=407 N

The force needed to get the table moving must be at least equal to the frictional force, which is equal to the product between the coefficient of friction and the weight of the all stuff:

F=F_f = \mu W=(0.22)(407 N)=89.5 N

7 0
3 years ago
An electron is moving directly toward you in a horizontal path when it suddenly enters a uniform magnetic field that is either v
blagie [28]

Answer:

To your left

Explanation:

The direction of the force exerted on charged particle due to a magnetic field is given by the right-hand-rule, where:

- The index finger indicates the direction of motion of the electron

- the middle finger gives the direction of the magnetic field

- the thumb gives the direction of the force if the particle is positively charged - otherwise, the direction is reversed

in this case, we have an electron (so, a negatively charged particle):

- The direction of motion (index finger) is horizontal, toward you

- The electron begins to curve upward as it enters the field, so this means that the force exerted on the electrons is upward --> the thumb must point downward (because the electron is negatively charged)

- The index finger gives us the direction of the magnetic field: therefore, to your left.

3 0
3 years ago
Although the temperature gradient changes from region to region in the homosphere, there is one gradient that stays the same. it
bezimeni [28]

Answer: the answer is air gradient

Explanation:

3 0
3 years ago
-2
photoshop1234 [79]

Answer:-2

Explanation:

7 0
2 years ago
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