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Whitepunk [10]
2 years ago
8

What is the solution to

" align="absmiddle" class="latex-formula">?
a) -16\geq x
b) -16\leq x
c) -8\geq x
d) -8\leq x
Mathematics
1 answer:
Murljashka [212]2 years ago
4 0
....................
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Help me out pls, <br> 20 points!
d1i1m1o1n [39]

Answer:

75.5 is not equivalent because 75 1/2% to a decimal is 0.775

Step-by-step explanation:

Hope this helps

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2 years ago
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B a C Which of these angles are adjacent angles?​
BigorU [14]

Answer: a and c

Step-by-step explanation:

I know it’s not b but isn’t adjacent angel two angels?

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2 years ago
Nick is now 7 times as old as harry. in 6 years, nick will be 5 times as old as harry. how old will harry be in 6 years?
zalisa [80]
Let,
Harry's age - x then Nick is 7x. 
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5 0
3 years ago
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A network provider investigates the load of its network. The number of concurrent users is recorded at fifty locations (thousand
beks73 [17]

Answer:

see explaination

Step-by-step explanation:

Using the formulla that

sum of terms number of terms sample mean -

Gives the sample mean as \mu=17.954

Now varaince is given by

s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97

and the standard deviation is s=\sqrt{9.97}=3.16

b) The standard error is given by

\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45

c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1

Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88

d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05

Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96

or a number which is less than 15.83-1.5(4.05)=9.76

As there is no such number so the given sample has no outliers

5 0
3 years ago
elliot counts a group of coims starting with rhe quarters his sister counts tje same coins.she starts counting the pennies.will
Leona [35]
Yes because they are counting the same group
5 0
3 years ago
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