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3 years ago

Puedo violar a mi hermana?

Physics

1 answer:

Trava [24]3 years ago

6 0

Interesante muy interesante

Pero no que estás diciendo???

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Newton second law of motion relates to force, what, and acceleration

yanalaym [24]

Answer:

Newtons second law of motion relates to force, inversely related to its <em><u>mass</u></em><em> </em>and acceleration.

4 0

3 years ago

What is the resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm2?

nadya68 [22]

The resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm² will be 0.74 ohm.

<h3>What is resistance?</h3>

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

ρ is the resistivity of tungsten = 5.6×10⁻⁸ (ohm m)

The relation of resistance with length and thickness is given by ;

$\rm R= \frac{\rho L}{A} \\\\ \rm R= \frac{5.6 \times 10^{-8}\times 2}{0.15 \times 10^{-6}} \\\\ R=0.74 \ ohm$

Hence, the resistance of tungsten wire will be 0.74 ohm.

To learn more about the resistance, refer to the link;

brainly.com/question/20708652

#SPJ1

3 0

2 years ago

A man pushes a box of 40kg up incline of 15°, if the man applies a horizontal force of 200N and the box moves up the plane a dis

Tatiana [17]

20 m is the correct answer

5 0

4 years ago

A speeding motorist traveling with velocity Vm is spotted by a police car. The police car is initially at rest, but the instant

Svetlanka [38]

Answer:

Explanation:

Given

Let us suppose police car and motorist travel in straight line and police car catches motorist after s distance

Distance travel by motorist

$s=v_mt$ ----1

Distance traveled by Police car

$s=ut+\frac{at^2}{2}$

$s=0+\frac{a_pt^2}{2}$

$s=\frac{a_pt^2}{2}$ ----2

from 1 & 2 we get

$t=\frac{2v_m}{a_p}$

(a)Velocity of Police car after t sec

$v=u+a_pt$

$v=0+a_p\times \frac{2v_m}{a_p}$

$v=2v_m$

(b)time taken by police car is

$t=\frac{2v_m}{a_p}$

(c)Distance travel by police car $=\frac{2v_m^2}{a_p}$

7 0

3 years ago

Calculate the KE of a 3.1 kg toy cart that moves at 4.8 m/s. Calculate the KE of the same cart at twice the speed.

lisov135 [29]

When v= 4.8 m/s:

E.K=mv²/2
=3,1(4.8)²/2
=35.712J

when v= 2(4.8):

E.K=mv²/2
=3.1(9.6)²/2
=142.848J

4 0

4 years ago