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AURORKA [14]
3 years ago
13

The distance versus time plot for a particular object shows a quadratic relationship. Which column of distance data is possible

for this situation?
Time (s) A. Distance (m) B. Distance (m) C. Distance (m) D. Distance (m) E. Distance (m)
0 0 2.00 9.00
1 1.00 4.00 18.00 1.00 1.00
2 4.00 6.00 27.00 0.50 0.25
3 9.00 8.00 36.00 0.33 0.11
4 16.00 10.00 45.00 0.25 0.06
5 25.00 12.00 54.00 0.20 0.04
6 36.00 14.00 63.00 0.16 0.02
A) column A
B) column B
C) column C
D) column D
E) column E ????
Physics
2 answers:
Vladimir79 [104]3 years ago
8 0
The correct choice is (C)

nataly862011 [7]3 years ago
7 0

Answer:

A). Column A

Explanation:

If distance vs time relation is a quadratic relation then it must be a relation that will follow the relation of time and distance with quadratic equation

So here we can say it must be like

x = k t^2

here we know that time is linearly given so we have

x = k 1^2

x = k 2^2

..............................

and so on

so here correct relation must be

x = 1

x = 2^2 = 4

x = 3^2 = 9

x = 4^2 = 16

so correct answer will be

A). Column A

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The arrow should be drawn upwards but the magnitude of force (arrow representing air resistance) should be shorter than the arrow representing gravity

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3 years ago
You walk for a speed of 1.1 m/s (meters per second) for 6.0 seconds and
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Answer:

Average speed, As = 2.2 [m/s]

Explanation:

To solve these types of problems we must remember that the average of the speeds is determined by dividing the distance over time.

With the first speed and the time of 6 [s] we can calculate the distance.

V = x/t

where:

x = distance [m]

V = velocity = 1.1 [m/s]

t = time = 6 [s]

x1 = V*t

X1 = 1.1*6

X1 = 6.6 [m]

Now with the second velocity and  6 [s], we can calculate the second distance.

X2 = 3.3*6

X2 = 19.8 [m]

Now we have to calculate the average speed. The total distance is x = x1 +x2

X = 19.8 + 6.6 = 26.4 [m]

and the total time is 12 [s]

Therefore:

As = 26.4/12

As = 2.2 [m/s]

5 0
3 years ago
Without the wheels, a bicycle frame has a mass of 8.29 kg. Each of the wheels can be roughly modeled as a uniform solid disk wit
trapecia [35]

Answer:

69.66 Joule

Explanation:

mass of bicycle frame, mf = 8.29 kg

mass of wheel, mw = 0.820 kg

radius, r = 0.343 m

velocity, v = 3.6 m/s

There are two wheels in the bicycle.

There are two types of kinetic energy of the system one is kinetic energy of rotation and another is rotational kinetic energy.

K = \frac{1}{2}m_{f}v^{2}+ 2\times \frac{1}{2}m_{w}v^{2}+ 2\times \frac{1}{2}I_{w}\omega^{2}

K = \frac{1}{2}m_{f}v^{2}+m_{w}v^{2}+ \frac{1}{2}\times m_{w}v^{2}

K = \frac{1}{2}m_{f}v^{2}+ \frac{3}{2}\times m_{w}v^{2}

K = \frac{1}{2}\times 8.29\times 3.6^{2}+ \frac{3}{2}\times 0.820\times 3.6^{2}

K = 69.66 J

3 0
3 years ago
Cart A and cart B are traveling in the same direction on a straight track. Cart A is moving at 9.25 m/s and cart B is moving at
Liula [17]

Answer:

The speed of cart B is 11.21 m/s.

Explanation:

Given that,

Speed of cart A = 9.25 m/s

Speed of cart B = 7.15 m/s

Mass of cart A = 72.0 kg

Mass of cart B = 55.0 kg

Speed of card A after collision = 6.15 m/s

We need to calculate the speed of cart B

Using conservation of momentum

m_{A}v_{A}+m_{B}v_{B}=m_{A}v_{A}+m_{B}v_{B}

Put the value into the formula

72.0\times9.25+55.0\times7.15=72.0\times6.15+55.0\times v_{B}

v_{B}=\dfrac{72.0\times9.25+55.0\times7.15-72.0\times6.15}{55.0}

v_{B}=11.21\ m/s

Hence, The speed of cart B is 11.21 m/s.

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Number 2 is the anser tropics
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