The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1
If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1
If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)
If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)
however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1
If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1
and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)
Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
You have to turn 65 into a decimal. That would be .65
They do 39/.65
You should get 60 as your final answer.
Answer:
10
Step-by-step explanation:
<h3>Calculating BC</h3><h3>BC = √2^2 + 11^2 </h3><h3>BC = √ 4+121</h3><h3>BC = √ 125 = 11.18</h3>
to find measure of angle C use sinerule
<h3>sinC/C = sinA/A</h3><h3>sinC/2= Sin90/11.18</h3><h3>SinC = 2×1/11.18</h3>
<h3>sinC = 2/11.18</h3><h3>sinC = (0.1788)</h3><h3>C = sin^-1(0.1788)</h3>
<h3>C = 10.305</h3><h3>C = 10 (approximately)</h3>