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lisabon 2012 [21]
4 years ago
8

190 grams of a hypothetical element called Clarkanium. If its atomic mass is 38, how many moles do you have in your measured sam

ple?
Physics
1 answer:
andrew-mc [135]4 years ago
5 0

5mole

Explanation:

Given parameters:

Mass of element  = 190g

Atomic mass = 38

Unknown:

Number of moles = ?

Solution:

A mole is a unit of measurement for quantifying particles.

 Number of moles = \frac{mass }{molar mass}

 The molar mass is the atomic mass here:

  Number of moles = \frac{190}{38} = 5mole

Learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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Water is flowing into a factory in a horizontal pipe with a radius of 0.0183 m at ground level. This pipe is then connected to a
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Answer:

0.0168 m^3/s

Explanation:

We are given that

r_1=0.0183 m

h_1=0

r_2=0.0420 m

h_2=12.6 m

Let P_1=P_2=P

By using Bernoulli theorem

P+\frac{1}{2}\rho v^2_1+\rho gh_1=P+\frac{1}{2}\rho v^2_2+\rho gh_2

\frac{1}{2}\rho v^2_1+\rho gh_1=\frac{1}{2}\rho v^2_2+\rho gh_2

v^2_1+2gh_1=v^2_2+2gh_2

A_1v_1=A_2v_2

v_1=\frac{A_2v_2}{A_1}

(\frac{A_2}{A_1})^2v^2_2+2g\times 0=v^2_2+2\times 9.8\times 12.6

(\frac{\pi r^2_2}{\pi r^2_1})^2v^2_2-v^2_2=246.96

v^2_2((\frac{r^2_2}{r^2_1})^2-1)=246.96

v^2_2=246.96\frac{r^4_1}{r^2_4-r^4_1}

v_2=\sqrt{246.96\frac{r^4_1}{r^4_2-r^4_1}}

v_2=\sqrt{246.96\times \frac{(0.0183)^4}{(0.042)^4-(0.0183)^4}}

v_2=3.038 m/s

Volume flow rate =A_2v_2

Volume flow rate =\pi r^2_2v_2=\pi (0.042)^2\times 3.038=0.0168 m^3/s

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