Distance = speed x time
distance = 116 x 10
distance = 1160 m
D, I believe would be the first minus the second vector.
To solve this I named the first vector as A and the second as B.
So... vector A - B = resultant
or A + (-B)
A negative indicates a direction of a vector so if we flip the direction the other way we have the first vector (A) pointing vertically upwards and then vector B pointing to the west.
Now we have to use the head to tail method, meaning that the head of the first vector has to connect with the tail of the other vector added.
So we should have something like this
(-B) < - - - - ^
|
| (A)
|
To add these two vectors, technically A - B, draw a line from the tail of A to the head of -B which would look like image D.
Hope this helped!
Answer:
v = 8.96 m/s
Explanation:
Initial speed of the ball, u = 10 m/s
It caught 1 meter above its initial position.
Acceleration due to gravity, 
We need to find the final speed of the ball when it is caught. Let is equal to v. To find the value of v, use third equation of motion as :
v = 8.96 m/s
So, the speed of the ball when it is caught is 8.96 m/s. Hence, this is the required solution.
Answer:
AAT-CAG-GT
AAT-CGA-GT
Explanation:
Because they are both missing one letter
an unexpected visitor as it begins making you feel uncomfortable but it's get calm
