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2 years ago

I need help on this question

Mathematics

1 answer:

Harlamova29_29 [7]2 years ago

6 0

Answer: Capitalism

Step-by-step explanation:

hope it helps

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Does (-15, -691) make the equation y = -51x - 74 true?<br><br><br>

dimulka [17.4K]

Well, we can input both variables to check and see if the numbers hold.

-691 = -51(-15) - 74

-691 = 765-64

-691 = 701

(-15, -691) does not make the equation true.

3 0

3 years ago

Read 2 more answers

Lucille wants to carpet her family room. Her family room is rectangular and has a length of 21 feet and a width of 17 feet. How

madreJ [45]

Answer:

$803.25

Step-by-step explanation:

Given data

Dimension for the room

Length= 21 ft

Width= 17ft

Area= L*W

Area= 21*17

Area= 357 ft^2

Lucy will need to get 357ft^2 of carpet

We are given that a square ft cost $2.25

Hence to carpet the room the cost will be $2.25*357= $803.25

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2 years ago

PLEASE HELP. EIGHTH GRADE MATH.

vampirchik [111]

Answer:

Cant see the picture can you zoom in?

Step-by-step explanation:

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2 years ago

Rick charges $50 plus $40 an hour to fix cars. Let x be the number of hours that he works and y be the overall cost that he char

Serjik [45]

Y= 40x+ 50 (i need 20 characters to post this so ignore)

5 0

3 years ago

Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .

anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

We need to begin with the definition of tangent:

$tan (x) =\frac{sin(x)}{cos(x)}$

So we can replace into our formula and we got:

$tan(x-y) = \frac{sin(x-y)}{cos(x-y)}$ (1)

We have the following identities useful for this case:

$sin(a-b) = sin(a) cos(b) - sin(b) cos(a)$

$cos(a-b) = cos(a) cos(b) + sin (a) sin(b)$

If we apply the identities into our equation (1) we got:

$tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}$ (2)

Now we can divide the numerator and denominato from expression (2) by $\frac{1}{cos(x) cos(y)}$ and we got this:

$tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}$

And simplifying we got:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

And this identity is satisfied for all:

$(x-y) \neq \frac{\pi}{2} +n\pi$

8 0

2 years ago