Answer : The rate law for the overall reaction is, ![Rate=k[A][B]](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5BB%5D)
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
As we are given the mechanism for the reaction :
Step 1 :
(slow)
Step 2 :
(fast)
Overall reaction : 
The rate law expression for overall reaction should be in terms of A and B.
As we know that the slow step is the rate determining step. So,
The slow step reaction is,

The expression of rate law for this reaction will be,
![Rate=k[A][B]](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5BB%5D)
Hence, the rate law for the overall reaction is ![Rate=k[A][B]](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5BB%5D)
False. harry styles all the way
(a) One form of the Clausius-Clapeyron equation is
ln(P₂/P₁) = (ΔHv/R) * (1/T₁ - 1/T₂); where in this case:
Solving for ΔHv:
- ΔHv = R * ln(P₂/P₁) / (1/T₁ - 1/T₂)
- ΔHv = 8.31 J/molK * ln(5.3/1.3) / (1/358.96 - 1/392.46)
(b) <em>Normal boiling point means</em> that P = 1 atm = 101.325 kPa. We use the same formula, using the same values for P₁ and T₁, and replacing P₂ with atmosferic pressure, <u>solving for T₂</u>:
- ln(P₂/P₁) = (ΔHv/R) * (1/T₁ - 1/T₂)
- 1/T₂ = 1/T₁ - [ ln(P₂/P₁) / (ΔHv/R) ]
- 1/T₂ = 1/358.96 K - [ ln(101.325/1.3) / (49111.12/8.31) ]
(c)<em> The enthalpy of vaporization</em> was calculated in part (a), and it does not vary depending on temperature, meaning <u>that at the boiling point the enthalpy of vaporization ΔHv is still 49111.12 J/molK</u>.
Answer:
Explanation:
None of the statement is true for both chemical and nuclear reactions. In chemical reactions, mass is always conserved and the type of atoms are also conserved.
I believe the correct answer from the choices listed above is option D. The power that was described is a battery. It <span>is a device consisting of one or more electrochemical cells with external connections provided to power electrical devices. Hope this answers the question. Have a nice day.</span>