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kykrilka [37]
3 years ago
11

GIVING BRAINLIEST :D

Chemistry
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

0.1 M molar NaaOH

Explanation:

M1V1= M2V2

M1 = 0.150M NaOH

V1=100 ml

V2=150 ml

M2=?

M2= M1V1/V2

M2= 0.150*100/150=0.1 M

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Calculate the pH of a buffer solution prepared by mixing 60.0 mL of 1.00 M lactic acid and 25.0 mL of 1.00 M sodium lactate.
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This problem could be solved easily using the Henderson-Hasselbach equation used for preparing buffer solutions. The equation is written below:

pH = pKa + log[(salt/acid]

Where salt represents the molarity of salt (sodium lactate), while acid is the molarity of acid (lactic acid). 

Moles of salt = 1 mol/L * 25 mL * 1 L/1000 mL = 0.025 moles salt
Moles of acid = 1 mol/L* 60 mL * 1 L/1000 mL = 0.06 moles acid
Total Volume = (25 mL + 60 mL)*(1 L/1000 mL) = 0.085 L

Molarity of salt = 0.025 mol/0.085 L = 0.29412 M
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pH = 3.86 + log(0.29412/0.70588)
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3 years ago
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Answer:

Explanation:

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Also, from the structure attached, it can be predicted that the approximate bond angles about the central atom is 120° (360 ÷ 3) since each of the three chlorine atoms is equally spaced about the central atom.

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