A. The factor by which a machine multiplies a force
Answer:
Heater power = 425 watts
Explanation:
Detailed explanation and calculation is shown in the image below
Answer:
a) ![m=0.17kg/s](https://tex.z-dn.net/?f=m%3D0.17kg%2Fs)
b) ![Ma=0.89](https://tex.z-dn.net/?f=Ma%3D0.89)
Explanation:
From the question we are told that:
Pressure ![P=60kPa](https://tex.z-dn.net/?f=P%3D60kPa)
Diameter ![d=3cm](https://tex.z-dn.net/?f=d%3D3cm)
Generally at sea level
![T_0=288k\\\\\rho_0=1.225kg/m^3\\\\P_0=101350Pa\\\\r=1.4](https://tex.z-dn.net/?f=T_0%3D288k%5C%5C%5C%5C%5Crho_0%3D1.225kg%2Fm%5E3%5C%5C%5C%5CP_0%3D101350Pa%5C%5C%5C%5Cr%3D1.4)
Generally the Power series equation for Mach number is mathematically given by
![\frac{p_0}{p}=(1+\frac{r-1}{2}Ma^2)^{\frac{r}{r-1}}](https://tex.z-dn.net/?f=%5Cfrac%7Bp_0%7D%7Bp%7D%3D%281%2B%5Cfrac%7Br-1%7D%7B2%7DMa%5E2%29%5E%7B%5Cfrac%7Br%7D%7Br-1%7D%7D)
![\frac{101350}{60*10^3}=(1+\frac{1.4-1}{2}Ma^2)^{\frac{1.4}{1.4-1}}](https://tex.z-dn.net/?f=%5Cfrac%7B101350%7D%7B60%2A10%5E3%7D%3D%281%2B%5Cfrac%7B1.4-1%7D%7B2%7DMa%5E2%29%5E%7B%5Cfrac%7B1.4%7D%7B1.4-1%7D%7D)
![Ma=0.89](https://tex.z-dn.net/?f=Ma%3D0.89)
Therefore
Mass flow rate
![\frac{\rho_0}{\rho}=(1+\frac{1.4-1}{2}(0.89)^2)^{\frac{1.4}{1.4-1}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Crho_0%7D%7B%5Crho%7D%3D%281%2B%5Cfrac%7B1.4-1%7D%7B2%7D%280.89%29%5E2%29%5E%7B%5Cfrac%7B1.4%7D%7B1.4-1%7D%7D)
![\frac{1.225}{\rho}=(1+\frac{1.4-1}{2}(0.89)^2)^{\frac{1.4}{1.4-1}}](https://tex.z-dn.net/?f=%5Cfrac%7B1.225%7D%7B%5Crho%7D%3D%281%2B%5Cfrac%7B1.4-1%7D%7B2%7D%280.89%29%5E2%29%5E%7B%5Cfrac%7B1.4%7D%7B1.4-1%7D%7D)
![\rho=0.848kg/m^3](https://tex.z-dn.net/?f=%5Crho%3D0.848kg%2Fm%5E3)
Generally the equation for Velocity at throat is mathematically given by
)
Where
![T_e=\frac{P_e}{R\rho}\\\\T_e=\frac{60*10^6}{288*0.842\rho}](https://tex.z-dn.net/?f=T_e%3D%5Cfrac%7BP_e%7D%7BR%5Crho%7D%5C%5C%5C%5CT_e%3D%5Cfrac%7B60%2A10%5E6%7D%7B288%2A0.842%5Crho%7D)
![T_e=248](https://tex.z-dn.net/?f=T_e%3D248)
Therefore
![V=0.89(1.4*288\sqrt{248})\\\\V=284](https://tex.z-dn.net/?f=V%3D0.89%281.4%2A288%5Csqrt%7B248%7D%29%5C%5C%5C%5CV%3D284)
Generally the equation for Mass flow rate is mathematically given by
![m=\rho*A*V](https://tex.z-dn.net/?f=m%3D%5Crho%2AA%2AV)
![m=0.84*\frac{\pi}{4}*3*10^{-2}*284](https://tex.z-dn.net/?f=m%3D0.84%2A%5Cfrac%7B%5Cpi%7D%7B4%7D%2A3%2A10%5E%7B-2%7D%2A284)
![m=0.17kg/s](https://tex.z-dn.net/?f=m%3D0.17kg%2Fs)
Answer : The final velocity of the ball is, 12.03 m/s
Explanation :
By the 3rd equation of motion,
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
where,
s = distance covered by the object = 6.93 m
u = initial velocity = 2.99 m/s
v = final velocity = ?
a = acceleration = ![9.8m/s^2](https://tex.z-dn.net/?f=9.8m%2Fs%5E2)
Now put all the given values in the above equation, we get the final velocity of the ball.
![v^2-(2.99m/s)^2=2\times (9.8m/s^2)\times (6.93m)](https://tex.z-dn.net/?f=v%5E2-%282.99m%2Fs%29%5E2%3D2%5Ctimes%20%289.8m%2Fs%5E2%29%5Ctimes%20%286.93m%29)
![v=12.03m/s](https://tex.z-dn.net/?f=v%3D12.03m%2Fs)
Thus, the final velocity of the ball is, 12.03 m/s
Answer:
200
Explanation:
A size sheets (also known as letter size) are 8.5 inches by 11 inches.
B size sheets (also known as ledger size) are 11 inches by 17 inches.
One B size sheet is twice as large as a A size sheet. So if you have 100 B size sheets and cut each one in half, you'll get 200 A size sheets.