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AfilCa [17]
3 years ago
5

In certain conditions, hydrogen gas produces the emission spectra shown below. What causes the bright lines seen in the spectra?

Chemistry
1 answer:
rusak2 [61]3 years ago
7 0

Answer:

a bright line spectrum is prodecued when an electron falls from a higher energy state

Explanation:

not sure if this is the exact answer you're looking for but it should be similar

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Answer: D.Solar power produces no carbon dioxide

Explanation:

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3 years ago
Calcium carbonate can break down to form calcium oxide and carbon dioxide.
DerKrebs [107]

Answer:

The answer to your question is the third choice.

Explanation:

                        CaCO₃  ⇒   CaO  +  CO₂

Check if the reaction is balanced or unbalanced

                  Reactants       Elements         Products

                           1              Calcium                1

                           1               Carbon                 1

                           3              Oxygen                3

As the number of atoms in the reactant is the same that the number of atoms in the products we conclude that the reaction is balanced.

So the correct answer is balanced because the total number of oxygen atoms is 3.

4 0
3 years ago
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What happens when an atom has more electrons than can fit in one energy
Rina8888 [55]

Answer:

If any atom has more electrons than one energy level can hold, then automatically the electron is accommodated in the next energy level (shell). The remaining extra electrons starts to fill the next energy level. This produces the valency of that particular atom.

Explanation:

8 0
4 years ago
Problem PageQuestion Iron(III) oxide and hydrogen react to form iron and water, like this: (s)(g)(s)(g) At a certain temperature
Marrrta [24]

Complete question

The complete question is shown on the first uploaded image

Answer:

The value is  K_c  =  2.69 *10^{-5}  

Explanation:

From the question we are told that

   The equation is  

           Fe_20_3_{(s)}+3H_{(g)}\to2Fe_{(s)}+3H_2O_{(g)}

Generally the equilibrium is mathematically represented as

        K_c  =  \frac{[H_2O]^2}{[H_2]^3}

Here [H_2O] is the concentration of water vapor which is mathematically represented as

      [H_2O ] =  \frac{n_w}{V_s }

Here V_s is the volume of the solution given as 8.9 L

n_w is the number of moles of water vapor which is mathematically represented as

        n_w  =  \frac{m_w}{Z_w}

Here  m_w  is the mass of water given as 2.00 g

and   Z_w  is the molar mass of water with value  18 g/mol

So  

         n_w  =  \frac{2}{18}

=>     n_w  = 0.11 \  mol

So

     [H_2O ] =  \frac{0.11}{8.9 }

=>   [H_2O ] = 0.01236 \  M

Also

[H] is the concentration of hydrogen gas which is mathematically represented as

      [H ] =  \frac{n_v}{V_s }

Here V_s is the volume of the solution given as 8.9 L

n_v is the number of moles of  hydrogen gas which is mathematically represented as

        n_v  =  \frac{m_v}{Z_v}

Here  m_w  is the mass of water given as 4.77 g

and   Z_v  is the molar mass of water with value  2 g/mol

So  

         n_w  =  \frac{4.77}{2}

=>     n_w  = 2.385 \  mol

So

     [H_2O ] =  \frac{2.385}{8.9 }

=>   [H_2O ] =  0.265 \  M

So

     K_c  =  \frac{( 0.01236 )^3}{ (0.265 )^2}

=>   K_c  =  2.69 *10^{-5}  

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