All categories

3 years ago

In certain conditions, hydrogen gas produces the emission spectra shown below. What causes the bright lines seen in the spectra?

Chemistry

1 answer:

rusak2 [61]3 years ago

7 0

Answer:

a bright line spectrum is prodecued when an electron falls from a higher energy state

Explanation:

not sure if this is the exact answer you're looking for but it should be similar

You might be interested in

Helpppppppppp please please

balandron [24]

#48 might be (A) but in not for sure

3 0

4 years ago

Read 2 more answers

Helppp ! Please :’)

Over [174]

Answer:

$\boxed{\sf \lambda \: = 1.282 \times {10}^{ 3} nm}$

Explanation:

Suppose an electron makes transition from n initial (ni) to n final (nf) then formula for wavelength is given by,

$\frac{1}{ \lambda} = R_H {Z}^{2} \big(\frac{1}{{n_f^2}} - \frac{1}{{n_i^2}} \big)$

Where,

λ is wavelength of photon
Rʜ is rydberg constant, the value of Rʜ is

109690 Cm-¹ in Puri Sharma Pathania standard book of physical chemistry &

109737 Cm-¹ according to Wikipedia

Z is the atomic number of atom, for hydrogen Z =1,

& according to given data, ni = 5, nf = 3

Solution:

Let's solve for wavelength,

Substituting all the given data in above formula,

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \big(\frac{1}{{3^2}} - \frac{1}{{5^2}} \big)$

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \big(\frac{1}{{9}} - \frac{1}{{25}} \big)$

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \times \frac{25 - 9}{25 \times 9}$

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \times \frac{16}{225}$

$\frac{1}{ \lambda} = 7800.18 \: \: cm ^{ - 1}$

$\lambda = 1.282 \times {10}^{ - 4} cm$

Now we know that, 1 cm = 10000000 nm,

Converting the wavelength from Cm → Nm

$\lambda \: = 1.282 \times {10}^{ - 4} \times {10}^{7}$

$\lambda \: = 1.282 \times {10}^{ - 4 + 7}$

$\sf \lambda \: = 1.282 \times {10}^{ 3} nm$

$\sf \small Thanks \: for \: joining \: brainly \: community!$

4 0

2 years ago

How many moles are in 6.4grams of copper

anzhelika [568]

Answer:

One mole of copper atoms has Avogadro number of copper atoms i.e. 6.022×10

atoms.

Given the mass of Copper is 6.4g

Number of Copper atoms in 6.4g =

molar mass

given mass

×Avogadro number

63.55

6.4

×6.022×10

copper atoms

=6.064×10

copper atoms

Explanation:

8 0

3 years ago

As a chlorine atom becomes a negative ion, the atom blanks an electron

Andrew [12]

Answer: increases by

As a chlorine atom becomes a negative ion, the atom "increases by" an electron

Explanation:

Chlorine atom has an atomic number of 17, and an electronic configuration of 1s2, 2s2 2p6, 3s2 3p5 showing 7 valence electrons in its outermost shell.

Hence, it receives a single electron to achieve a stable octet structure with electronic configuration of

1s2, 2s2 2p6, 3s2 3p6. Therefore, Cl- is a univalent negative ion with 8 valence electrons in its outermost shell. The increase is shown below

Cl + e- --> Cl-

Thus, as a chlorine atom becomes a negative ion, the atom "increases by" an electron

7 0

3 years ago

Balance Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O

Delicious77 [7]

Equation balance:

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

2Al(OH)3+3H2SO4

H=12

SO4=3

O=6

Al=2

Al2(SO4)3+6H2O

H=12

SO4=3

O=6

Al=2

8 0

3 years ago