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Reptile [31]
3 years ago
12

A Carnot engine has an efficiency of 83.0% and performs 4500 J of work every cycle. How much energy is discharged to the lower t

emperature reservoir every cycle?
Physics
1 answer:
ololo11 [35]3 years ago
6 0

We will start by finding the heat in state one through the thermal efficiency or efficiency of a thermal machine is a coefficient or dimensionless ratio calculated as the ratio of the energy produced (in an operating cycle) and the energy supplied to the machine. Mathematically it is the relationship between the work generated and the heat emanated.

So,

\eta = \frac{W}{Q_1} \rightarrow Q_1 = \frac{W}{\eta}

Q_1 = \frac{4500}{0.83}

Q_1 = 5421J

The total change of energy is equivalent to 4500J and this is equal by conservation of energy to the total change in heat. So:

W = \Delta Q

W = Q_1-Q_2

4500 = 5421- Q_2

Q_2 = 921.68 J

Therefore the energy which is discharged to the lower temperature reservoir every cicle is 921.7J

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Natural selection is the mechanism that?
Nikitich [7]

Answer:

weeds out the weak, sick, and old by killing them

8 0
4 years ago
If a rock on a cliff starts with 3,000 J of GPE and 0 J of KE and ends with 0 J of GPE and 5,000 J of KE, what law of physics wo
alexgriva [62]

The law of physics that this scenario would violate is the law of conservation of energy.

<h3>What is the law of conservation of energy?</h3>

The law of conservation of energy states that energy possessed by an object or physical body can neither be created nor destroyed but can only be transformed from one form to another.

This ultimately implies that, the energy possessed by the rock at the beginning must be equal to the energy possessed by the rock at the end in accordance with the law of conservation of energy.

Read more on energy here: brainly.com/question/1242059

6 0
2 years ago
A square loop of wire with a small resistance is moved with constant speed from a field free region into a region of uniform B f
Misha Larkins [42]

Answer:

A) False

B) False

C) True

D) False

Explanation:

A) False, because when leaving the field, the coil experiences a magnetic force to the right.

B) When the loop is entering the field, the magnetic flux through it will increase. Thus, induced magnetic field will try to decrease the magnetic flux i.e. the induced magnetic field will be opposite to the applied magnetic field. The applied magnetic field is into the plane of figure and thus the induced magnetic field is out of the plane of figure. Due to that reason, the current would be counterclockwise. So the statement is false.

C) When the loop is leaving the field, the magnetic flux through the loop will decrease. Thus, induced magnetic field will try to increase the magnetic flux i.e. the inducued magnetic field will be in the same direction as the applied magnetic field. The applied magnetic field is into the plane of figure and thus the induced magnetic field is also into the plane of figure. Due to that reason, the current would be clockwise. So the statement is true.

D) False because when entering the field magnetic force will be toward left side

8 0
3 years ago
Predict the speed of a car after 10.0 s when the car’s speed follows
andreev551 [17]

Answer:

48 m/s

Explanation:

The time is 10 seconds

The speed of the car after 10 seconds when the relationship is 4.8 m/s^2 × time can be calculated as follows

= 4.8 × 10

= 48

Hence the speed is 48 m/s

7 0
4 years ago
A mass is oscillating up and down on a spring. In the above graph of
melomori [17]

Answer:

<em>Amplitude= 8 m</em>

Explanation:

<u>The Amplitude of a Wave</u>

Sinusoidal Function  refers to a mathematical curve with a smooth and periodic oscillation. Its name comes from the sine function and is characterized by the amplitude or the maximum displacement or distance moved by a point on a vibrating body measured from its equilibrium position.

To calculate the amplitude from a graph, we measure the maximum point and the minimum point the wave reaches. Then we subtract both values and divide the result by 2.

The shown wave in the figure has a maximum value of 8 m and a minimum value of -8 m. The distance from the maximum to the minimum is 8-(-8)= 16 m, thus the amplitude is 16/2= 8m.

Amplitude= 8 m

5 0
3 years ago
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