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AfilCa [17]
3 years ago
6

*100 POINTS

Engineering
2 answers:
mylen [45]3 years ago
8 0

Answer:

D

Explanation:

lisov135 [29]3 years ago
7 0
I think it’s A i could be wrong honestly this is just a guess from my knowledge
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Use the following assumptions for problems 1 and 2:
Salsk061 [2.6K]

Answer:

The text file attached has the detailed solution of all the parts individually.

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6 0
3 years ago
Please read and answer each question carefully.
Klio2033 [76]

the answer is (c)

After the vehicle is involved in a car accident or fire

5 0
4 years ago
Do not discharge wastewater into storm sewers because they flow directly into local surface waters. A. true B. false
enot [183]

Answer:

True

Explanation:

Wastewater should never be discharged into storm sewers. Storm sewers are constructed to store rainwater.  

Rainwater passes through storm sewers to the nearest underground water resource if the wastewater discharge into storm sewers, then they will also pollute the ground water, so usually the dirty water is not put in the storm sewers.

3 0
3 years ago
A long cylindrical black surface fuel rod of diameter 25 mm is shielded by a surface concentric to the rod. The shield has diame
Elden [556K]

Answer:

surface temp of fuel rod = 678.85 K

Explanation:

Given data :

D1 = 25 mm

D2 = 50 mm

T2 = 335 k

T∞ = 300 k

hconv = 0.15 w/m^2.k

ε2 = 0.05

ε1 = 1

Determine energy at Q23

Q23 = Qconv + Qrad

attached below is the detailed solution

Insert given values into equation 1 attached below to obtain the surface temperature of the fuel rod ( T1 )

4 0
3 years ago
A beam of span L meters simply supported by the ends, carries a central load W. The beam section is shown in figure. If the maxi
saw5 [17]

Answer:

W = 11,416.6879 N

L ≈ 64.417 cm

Explanation:

The maximum shear stress, \tau_{max}, is given by the following formula;

\tau_{max} = \dfrac{W}{8 \cdot I_c \cdot t_w} \times \left (b\cdot h^2 - b\cdot h_w^2 + t_w \cdot h^2_w \right )

t_w = 1 cm = 0.01

h = 29 cm = 0.29 m

h_w = 25 cm = 0.25 m

b = 15 cm = 0.15 m

I_c = The centroidal moment of inertia

I_c = \dfrac{1}{12} \cdot \left (b \cdot h^3 - b \cdot h_w^3 + t_w \cdot h_w^3 \right )

I_c = 1/12*(0.15*0.29^3 - 0.15*0.25^3 + 0.01*0.25^3) = 1.2257083 × 10⁻⁴ m⁴

Substituting the known values gives;

I_c = \dfrac{1}{12} \cdot \left (0.15 \times 0.29^3 - 0.15 \times 0.25^3 + 0.01 \times 0.25^3 \right )  = 1.2257083\bar 3 \times 10^{-4}

I_c = 1.2257083\bar 3 × 10⁻⁴ m⁴

From which we have;

4,500,000 = \dfrac{W}{8 \times 1.225708\bar 3 \times 10 ^{-4}\times 0.01} \times \left (0.15 \times 0.29^2 - 0.15 \times 0.25^2 + 0.01 \times 0.25^2 \right )

Which gives;

W = 11,416.6879 N

\sigma _{b.max} = \dfrac{M_c}{I_c}

\sigma _{b.max} = 1500 N/cm² = 15,000,000 N/m²

M_c = 15,000,000 × 1.2257083 × 10⁻⁴ ≈ 1838.56245 N·m²

From Which we have;

M_{max} = \dfrac{W \cdot L}{4}

L = \dfrac{4 \cdot M_{max}}{W} = \dfrac{4 \times 1838.5625}{11,416.6879} \approx 0.64417

L ≈ 0.64417 m ≈ 64.417 cm.

4 0
3 years ago
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