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Dahasolnce [82]
3 years ago
5

You throw a rock horizontally off a cliff with a speed of 20 m/s. after two seconds, the magnitude of the velocity of the rock i

s closest to
Physics
1 answer:
Ksivusya [100]3 years ago
7 0
So the magnitude of the resultant vector of the vertical and horizontal together is a right triangle with 20 on one side and 19.62 going down. 
<span>A^2 + B^2 = C^2 </span>
<span>20^2 + 19.62^2 = C^2 </span>
<span>400 + 385 = C^2 </span>
<span>C = 28.0 m/s magnitude </span>
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If a force of 3000 N is applied to a large rock, but the rock does not move, how much work is done on the rock?
kkurt [141]

Answer:

No work was done.

W = 0

Explanation:

Work is said to be done whenever a force of one newton moves a body of one kilogram through a distance of one meter. Meaning the applied force has to move the body from a point of rest through certain distance.

Work = force × distance

So, in the case of this question, we only have the force been applied, but no distance was covered. Hence, no work was done.

W = 3000× 0 meter

W = 0

8 0
3 years ago
What is the average power dissipated by a resistor of resistance R = 25 Ω in an LRC circuit for which the power factor is equal
olga55 [171]

Answer:

0.08 w

Explanation:

AVERAGE POWER : Average power is defined as the average work per unit time. average power is denoted by P its depend on the voltage current and power factor.

the expression for the average power is given as

P=V_rI_r cosΦ

We have given maximum voltage =8 volt

V_r=\frac{8}{1.414}

power factor =.25

resistance =25Ω

power factor =\frac{R}{Z}

power factor=\frac{25}{Z}

From here Z=100

P=\frac{8}{1.414} ×\frac{v_r}{Z} ×cosΦ

=5.6577×0.05677×0.25

=0.08w

3 0
3 years ago
Question 3
Lina20 [59]

Answer: D

Explanation:

7 0
3 years ago
Tripling the displacement from equilibrium of an object in simple harmonic motion will bring about a change in the magnitude of
Anni [7]

Answer:

acceleration will be tripled.

Explanation:

We know, when an object is performing Simple harmonic motion, the force

experience by it is directly proportional to its displacement from its mean position.

Also, F = ma , therefore, acceleration is also proportional to its displacement .

Now, F = kx

Therefore, a=\dfrac{k\ x}{m}

If we triple the displacement i.e, 3x.

Acceleration a'=\dfrac{k(3x)}{m}=3a.

Therefore, acceleration is also tripled.

Hence, this is the required solution.

7 0
3 years ago
A glass plate 2.25 mm thick, with an index of refraction of 1.80, is placed between a point source of light with wavelength 620
-BARSIC- [3]

Answer:

There are 2.71x10⁴ wavelengths between the source and the screen.

Explanation:

The number of wavelengths (N) can be calculated as follows:

N = \frac{d_{g}}{\lambda_{g}} + \frac{d_{a}}{\lambda_{a}}    

Where:

d_{g}: is the distance in glass = 2.25 mm

d_{a}: is the distance in air = 1.50 cm - 0.225 cm = 1.275 cm

\lambda_{g}: is the wavelength in glass

\lambda_{a}: is the wavelength in air = 620 nm

To find the wavelength in glass we need to use the following equation:

n_{g}*\lambda_{g} = n_{a}*\lambda_{a}

Where:

n_{g}: is the refraction index of glass = 1.80

n_{a}: is the refraction index of air = 1

\lambda_{g} = \frac{\lambda_{a}}{n_{g}} = \frac{620 nm}{1.80} = 344.4 nm

Hence, the number of wavelengths is:

N = \frac{d_{g}}{\lambda_{g}} + \frac{d_{a}}{\lambda_{a}}

N = \frac{2.25 \cdot 10^{-3} m}{344.4 \cdot 10^{-9} m} + \frac{1.275 \cdot 10^{-2} m}{620 \cdot 10^{-9} m}                                    

N = 2.71 \cdot 10^{4}

Therefore, there are 2.71x10⁴ wavelengths between the source and the screen.

I hope it helps you!

5 0
3 years ago
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