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weeeeeb [17]
3 years ago
12

2. The Density of Water is 1.0000g/cm3. Based on this property of water,

Chemistry
1 answer:
Vanyuwa [196]3 years ago
7 0

Answer:

if the object sank then that object has a greater density then water. if the object floated then its density is lower then water.

Explanation:

lets say object 1 has a density of 24/cm3. the density is greater then water (1.0000g/cm3) so it would sink. now lets say object 2 has a density of 0.79383g/cm3 since it's less then the density of water (1.0000g/cm3) it would float.

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4 NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)
Mariulka [41]

Answer:

0.9 moles of water

Explanation:

Use mole ratios:

5 : 6

divide by 5 on both sides

1 : 1.2

multiply by 0.75 on both sides

0.75 : 0.9

So the result is 0.9 moles of water

(Please correct me if I'm wrong)

5 0
2 years ago
Based on the equation, determine what happens to the period, T, as the frequency increases.
ryzh [129]
The answer is c but it might be b it’s be
4 0
3 years ago
Read 2 more answers
The paths in which electrons travel are called what ovals ,paths,circles,orbitals
PolarNik [594]
The paths in which electrons travel are called orbitals.

8 0
3 years ago
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C3H8 + 5 O2 → 3 CO2 + 4 H2O<br> What is the number of atoms on each side of the equation?
Roman55 [17]

Answer: 1.2642*10²⁵ on both sides

Explanation:

First check how many moles are there on each side.
Since this is a balanaced equataion the number of moles on each side is the same thus the number of atoms is also same on both sides

There are 3 moles of carbon and 8 moles of hydrogen in C3H8
and 2 moles of oxygen in O2 but there 5 infront so 2*5 is 10
Number of moles on the right is 10+8+3 = 21

Now use Avogrado's constant

21 Moles* (6.02*10²³)/Mol
= 21*6.02*10²³

= 1.2642*10²⁵

6 0
2 years ago
Read 2 more answers
A sample of nitrogen gas, (N2), occupies 45.0 mL at 27.00∘C and 80.0 kPa. What will be the pressure if the gas is cooled to −73.
maxonik [38]

Answer:

The new pressure is 53.3 kPa

Explanation:

This problem can be solved by this law. when the volume remains constant, pressure changes directly proportional as the Aboslute T° is modified.

T° increase → Pressure increase

T° decrease → Pressure decrease

In this case, temperature was really decreased. So the pressure must be lower.

P₁ / T₁ = P₂ / T₂

80 kPa / 300K =  P₂/200K

(80 kPa / 300K) . 200 K = P₂ →  53.3 kPa

6 0
3 years ago
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