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3 years ago

9

The graph shows the results of a race between Peter and Stuart. Both boys begin the race at the same time.

1 answer:

Drupady [299]3 years ago

5 0

Answer:it would be the 2nd , 3rd, 5th,

one

Step-by-step explanation:

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A ball is dropped from a height of 12 feet and returns to a height that is one-

nasty-shy [4]

Answer:

0.375

Step-by-step explanation:

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3 years ago

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Hey I need these by 8am or I'm screwed,

tiny-mole [99]

34.4 / 4 = 8.6

The value 214.01 is greater.

2.5 x 10^3 = 2,500

1 M = 100 CM
2 M = 200 CM
3 M = 300 CM
4 M = 400 CM
5 M = 500 CM
6 M = 600 CM
7 M = 700 CM

If you want detailed explanations after you get done with your classes ill be glad to explain. Happy studying!

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4 years ago

Find the output for each input of y = -2x.

VashaNatasha [74]

The 2nd choice down in correct.

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3 years ago

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Ms. Johnson is drawing a floor plan of her square room that has an area of 100 ft2. She is using the scale of 0.5 inch =2 ft. Wh

algol [13]

Answer:

it's 2.5 inches cool profile pic to

Step-by-step explanation:

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3 years ago

Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.

Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

$|AB|=\sqrt{(4--1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{5^2+(0)^2}$

$\Rightarrow |AB|=\sqrt{25}$

$\Rightarrow |AB|=5 units$ .

The length of side BC

$|BC|=\sqrt{(3-4)^2+(-1-2)^2}$

$\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}$

$\Rightarrow |BC|=\sqrt{1+9}$

$\Rightarrow |BC|=\sqrt{10}$

The length of side AC

$|AC|=\sqrt{(3--1)^2+(-1-2)^2}$

We simplify to obtain;

$|AC|=\sqrt{(3+1)^2+(-3)^2}$

$\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}$

$|AC|=\sqrt{16+9}$

$|AC|=\sqrt{25}$

$|AC|=5\:units$

Since $|AC|=5\:units=|AB|$ , the given triangle is an isosceles triangle.

The correct answer is

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4 years ago

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