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SVEN [57.7K]
3 years ago
6

In a paragraph below, explain at least three key pieces of information about the moon.

Chemistry
1 answer:
lukranit [14]3 years ago
4 0

Explanation:

Nasa pic ang sagot yan ang sagot ko sa isa mo pang question

<h2><u>#CARRYONLEARNING</u><u> </u></h2><h2><u>#STUDYWELL</u><u> </u></h2>

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What is the interval used on the y-axis of this graph?
bezimeni [28]

Answer:

5

Explanation:

the numbers go up by 5

7 0
3 years ago
I need help with all of these questions
mafiozo [28]
Number five is decrease
7 0
3 years ago
Which numbers are shown in the symbol for a radioactive nuclide?
stira [4]

Answer:

The answer is C.

"The atomic number and mass number."

Explanation:

Got it right on Edge!

Have a good day!

7 0
2 years ago
Read 2 more answers
Many double-displacement reactions are enzyme-catalyzed via the "ping pong" mechanism, so called because the reactants appear to
zhenek [66]

Answer:

<u>D. It will decrease by a factor of 4</u>

Explanation:

According to the question , the equation follows :

A+B\rightarrow C+D

Rate law : This states the rate of reaction is directly proportional to concentration of reactants with each reactant raised to some power which may or may not be equal to the stoichiometeric coefficient.

Rate\ \alpha [A]^{a}[B]^{b}

r=[A]^{a}[B]^{b}.................(1)

STEP": First, find out the power "a" and "b"

a+b = 3 (because it is given that the reaction follow 3rd order-kinetics)

According to question, <u><em>doubling the concentration of the first reactant causes the rate to increase by a factor of 2 means,</em></u>

r' = 2r if [A'] = 2[A]

Here [B] is uneffected means [B']=[B]

hence new rate =

r'=[A']^{a}[B']^{b}

Put the value of [A'] , [B'] and r' in the above equation:

2r=[2A]^{a}[B]^{b}...........(2)

Divide equation (1) by (2) we , get

\frac{2r}{r}=\frac{[2A]^{2}[B]^{b}}{[A]^{a}[B]^{b}}

2= 2(\frac{A}{A})^{a}\times (\frac{B}{B})^{b}

Here A and A cancel each other

B and B cancel each other

We get,

2= 2^{a}\times 1^{b}

1^b = 1 ( power of 1 = 1)

2= 2^{a}

This is possible only when a = 1

We know that : a + b = 3

1 + b = 3

b =3 -1  = 2

b = 2

Hence the rate law becomes :

r=[A]^{a}[B]^{b}

<u>r=[A]^{1}[B]^{2}.............(3)</u>

Look in the question now, it is asked to calculate the concentration of [B],if  cut in half

Hence

[B']=1/2[B]

Insert the value of [B'] in equation (3)

r'=[A]^{1}[B']^{2}

r'=[A]^{1}(\frac{1}{2}[B])^{2}

r'=\frac{1}{4}[A]^{1}[B]^{2}............(a)

But

r=[A]^{a}[B]^{b}..............(b)

Compare equation (a) and (b) , we get

new rate r' =

<u>r' = 1/4 r</u>

7 0
2 years ago
8. When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. I
Julli [10]

Hey there!:

8) ΔTb = i*Kb*m  

 m is molality

 Since same number of mol is added to same amount of water in both cases

m will be same for both

is 1 for glucose since it is covalent compound

is 4 of Al(NO3)3 as it breaks into 1 Al₃⁺ and 3 NO₃⁻

So,  ΔTb will be 4 times in aluminum nitrate case

So, boiling point will change by 4ºC


9) use Q = m*  L

L =  heat of vaporization so:

T1=T2=100ºC

5.40 * 1000 => 5400  cal/g

Q =   5400 / 540

Q = 10 grams


Hope that thlps!

5 0
3 years ago
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