Answer: After 4710 seconds, 1/8 of the compound will be left
Explanation:
Using the formulae
Nt/No = (1/2)^t/t1/2
Where
N= amount of the compound present at time t
No= amount of compound present at time t=0
t= time taken for N molecules of the compound to remain = 4710 seconds
t1/2 = half-life of compound = 1570 seconds
Plugging in the values, we have
Nt/No = (1/2)^(4710s/1570s)
Nt/No = (1/2)^3
Nt/No= 1/8
Therefore after 4710 seconds, 1/8 molecules of the compound will be left
(4) total number of valence electrons, because they exist in the same group.
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I don’t know what to do with the answer I don’t know how you feel sorry I didn’t
Use PV = nRT
(2 atm)(.3 liters) = n(8.314 mol*K)(303°K)
.6 = n(2519.142)
Divide by 2519.142
n = .00023818 mols of HCl * 36.46g of HCl/ 1 mol of HCl
Grams of HCl = 0.00868
