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Paul [167]
3 years ago
10

Determine the number of protons, neutrons, and electrons for a neutral potassium-41 isotope.

Chemistry
1 answer:
Sphinxa [80]3 years ago
6 0


Atomic number is equal to the number of electrons in a neutral atom. ... Niobium has an atomic number of 41. ... Determine the number of protons, electrons, and neutrons for each isotope described ... Potassium-41. 19
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Choose all of the following mole ratios that are correct for the reaction given below. Be sure to choose all that apply.
Dennis_Churaev [7]

Answer:

2 moles NH3 = 1 mole of N2

3 moles of H2 = 1 mole of N2

3 moles of H2 = 2 moles of NH3

Explanation:

The balanced equation for the reaction is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Thus, we can say that:

1 mole of N2 = 3 moles of H2

1 mole of N2 = 2 moles of NH3

3 moles of H2 = 2 moles of NH3

Thus, considering the options given above, the right answers to the question are:

2 moles NH3 = 1 mole of N2

3 moles of H2 = 1 mole of N2

3 moles of H2 = 2 moles of NH3

5 0
3 years ago
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tigry1 [53]

Answer:

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6 0
3 years ago
Your friend challenged you to a race you know in order to beat him you must run 15 meters within 20 seconds in the northern dire
Marat540 [252]

Answer:

.75 meter north

Explanation:

v = d/t

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7 0
3 years ago
PLEASE HELPPPPPPPPPPPPPP
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Answer:

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4 0
3 years ago
3.604m + 104.29m + 3.1m + 17.41m. The sum expressed in the correct number of significant figures is
dedylja [7]

Answer:

128.4 m

Explanation:

3.604m + 104.29m + 3.1m + 17.41m

Add all the values

= 128.404 m

The significant figure rule for addition is for the sum to have the same number of decimal places as the value with the least number of decimal places. In the addition sentence 3.604m + 104.29m + 3.1m + 17.41m, the value with the least number of decimal places is 3.1, which has 1 decimal place. Therefore, we round our sum so that it also has 1 decimal place.

128.404 m

= 128.4 m

I hope this helps!

7 0
3 years ago
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