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katrin2010 [14]
3 years ago
5

What are the coefficients for the reaction _Cl2O5 + _H2O → _HClO3 once it is balanced?

Chemistry
2 answers:
Eva8 [605]3 years ago
7 0
It is B (1,1,2) because when you plug those numbers in, there are the same amount of elements in the reactant and product, just rearranged as the format A+B <span>→  AB, because this is a synthesis reaction.</span>
natita [175]3 years ago
6 0

Answer: The correct option is B.

Explanation: We are given an unbalanced chemical equation, so to find out the actual coefficients for the reaction, we need to balance it.

Balancing a chemical equation, we get

Cl_2O_5+H_2O\rightarrow 2HClO_3

The coefficients for the reaction as seen from above equation are 1, 1, 2.

The correct option is B.

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Wich of the following is a unit of volume in the english system of mesurement​
ch4aika [34]

Answer:

uhh its gallon

Explanation:

5 0
4 years ago
If 0.2 M Ag+, 2 M Ba2+, and 2 M Ca2+ are added to a Na2SO4 solution, which will precipitate first? (Ksp of Ag2SO4 = 1.4 x 10-5,
Sedbober [7]
A.

This is because BaSO₄ has the lowest solubility product out of all the substances.
7 0
3 years ago
A 5.024 mg sample of an unknown organic molecule containing carbon, hydrogen, and nitrogen only was burned and yielded 13.90 mg
Dafna1 [17]

Answer:

C8H17N

Explanation:

Mass of the unknown compound = 5.024 mg

Mass of CO2 = 13.90 mg

Mass of H2O = 6.048 mg

Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:

For carbon, C:

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C = 12/44 x 13.90 = 3.791 mg

For hydrogen, H:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H = 2/18 x 6.048 = 0.672 mg

For nitrogen, N:

Mass N = mass of unknown – (mass of C + mass of H)

Mass of N = 5.024 – (3.791 + 0.672)

Mass of N = 0.561 mg

Now, we can obtain the empirical formula for the compound as follow:

C = 3.791 mg

H = 0.672 mg

N = 0.561 mg

Divide each by their molar mass

C = 3.791 / 12 = 0.316

H = 0.672 / 1 = 0.672

N = 0.561 / 14 = 0.040

Divide by the smallest

C = 0.316 / 0.04 = 8

H = 0.672 / 0.04 = 17

N = 0.040 / 0.04 = 1

Therefore, the empirical formula for the compound is C8H17N

8 0
3 years ago
The average propane cylinder for a residential grill holds approximately 18 kg of propane. how much energy (in kj) is released b
Angelina_Jolie [31]
Let's begin with the basic values  that will be used in the solution.

The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.

Molar Mass Calculation is done as like that
C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M(
C3H8)= 3*12+ 8*1= 44 g

Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (
ΔHc°).  

ΔHc° of propane equals -2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out ( an exothermic reaction ).

Let's write the combustion reaction.
C3H8 + O2 ---> CO2 + H20 (unbalanced) 
ΔHc° = -2202 kj/mol

Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.
mole=mass/molar mass ; n=m/M ; n= 20000 g /44 (g/mol)=454 mole

1 mole propane releases 2202 kj energy.
454 mole propane release 2202 kj *454= 1000909 kj

The answer is 1000909 kj.



6 0
4 years ago
6 trillion quadrn edgar
Mice21 [21]
6 trillion quadrant
7 0
3 years ago
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