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Anon25 [30]
3 years ago
5

How many elements and atoms are in tylanol

Chemistry
1 answer:
RoseWind [281]3 years ago
7 0

Answer:

Element Symbol # of Atoms

Hydrogen H          9

Carbon C          8

Nitrogen N           1

Oxygen O          2

Explanation:

there are 5 elements

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What is the density of an 820 g sample of pure silicon occupying a 350 cm3 container
vodka [1.7K]

Answer:

2.343 g/ cm³

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

density = ?

volume= 350 cm³

mass= 820 g

Now we will put the values in the formula,

d= m/v

d= 820 g/ 350 cm³

d= 2.343 g/ cm³

The density of silicon is 2.343 g/ cm³

6 0
3 years ago
You are attempting to collect pure hydrogen gas by reacting hydrochloric acid with zinc. Based on the amount of reactants you us
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A !.!.!.!.!.!!..!.!.!.!.!.!.!.!!.!..!!.!.!.!.!.!.!.!.!.!.!!.!.!.!.!
7 0
3 years ago
Could the Periodic Table be arranged differently?
coldgirl [10]

Answer:

No because it is stayed that way and you can't define them differently.

7 0
3 years ago
Read 2 more answers
Dissolved hydrofluoric acid reacts with dissolved sodium hydroxide to form water and aqueous sodium fluoride
GalinKa [24]

Answer:

HF(aq)+NaOH(aq)→NaF(aq)+H2O(l)

Explanation:

Complete question

Dissolved hydrofluoric acid reacts with dissolved sodium hydroxide to form water and aqueous sodium fluoride. What is the net ionic equation

Equilibrium equation between the undissociated acid and the dissociated ions

HF(aq)⇌H+(aq)+F−(aq)

Sodium hydroxide will dissociate aqueous solution to produce sodium cations, Na+, and hydroxide anions, OH−

NaOH(aq)→Na+(aq)+OH−(aq)

Hydroxide anions and the hydrogen cations will neutralize each other to produce water.

H+(aq)+OH−(aq)→H2O(l)

On combining both the equation, we get –  

HF(aq)+Na+(aq)+OH−(aq)→Na+(aq)+F−(aq)+H2O(l)

The Final equation is  

HF(aq)+NaOH(aq)→NaF(aq)+H2O(l)

5 0
3 years ago
A 0.580 g sample of a compound containing only carbon and hydrogen contains 0.480 g of carbon and 0.100 g of hydrogen. At STP, 3
Sati [7]

Answer:

Molecular formula for the gas is: C₄H₁₀

Explanation:

Let's propose the Ideal Gases Law to determine the moles of gas, that contains 0.087 g

At STP → 1 atm and 273.15K

1 atm . 0.0336 L = n . 0.082 . 273.15 K

n = (1 atm . 0.0336 L) / (0.082 . 273.15 K)

n = 1.500 × 10⁻³ moles

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Now we propose rules of three:

If 0.580 g of gas has ____ 0.480 g of C _____ 0.100 g of C

58 g of gas (1mol) would have:

(58 g . 0.480) / 0.580 = 48 g of C  

(58 g . 0.100) / 0.580 = 10 g of H

 48 g of C / 12 g/mol = 4 mol

 10 g of H / 1g/mol = 10 moles

7 0
3 years ago
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