Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).
pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.
LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:
[LiOH]= [OH-]= 0.073 M
Replacing in the definition of pOH:
pOH= -log (0.073 M)
<u><em>pOH= 1.14 </em></u>
In summary, the pOH of the aqueous solution is 1.14
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Answer:
63.546
Explanation:
The Average atomic mass is calculated using the formula:
sum of the product of the atomic masses and their relative abundances all divided by 100 or total abundance
Answer is: <span>B) -50.2 kJ.
Balanced chemical reaction: </span>N₂(g) + 3H₂(g) → 2NH₃(g) ΔH = -<span>100.4 kJ.
This is exothermic reaction, because heat is released and energy is include as product of chemical reaction.
Make proportion, two moles of ammonia released 100.4 kJ of heat, then one mole of ammonia released:
2 mol(NH</span>₃) : (-100.4 kJ) = 1 mol : ΔH.
ΔH = -50.2 kJ; <span>heat released per mole of NH</span>₃.
Answer:
400 mL of 4% salt solution and 600 mL of 16% salt solution need to be mixed
Explanation:
Let's assume concentration of brine salt solutions are in %(w/v) unit.
Final mixture has a concentration of 11.2% salt and volume of 1 L or 1000 mL
Hence, amount of salt in final mixture = 
Suppose x mL of 4% salt solution and (1000-x) mL of 16% salt solution need to be mixed to get final mixture
So, amount of salt in x mL of 4% salt solution = 
amount of salt in x mL of 16% salt solution =
Hence, 
or, 
So, 400 mL of 4% salt solution and 600 mL of 16% salt solution need to be mixed
