Answer:
2.87m
Explanation:
Using the law of gravitation to solve this question
F = GMm/r²
G is the gravitational constant
M and m are the masses
r is the distance between the masses
Substitute the given values
G = 6.67×10^-11 m³/kgs²
M =8.8 x 10^6 kg
m = 5.6 x 10^5 kg
F =440N
400 = 6.67×10^-11×8.8 x 10^6 ×5.6 x 10^5/r²
400r² = 328.698×10
400r² = 3286.98
r² = 3286.98/400
r² = 8.21745
r = √8.21745
r = 2.87m
Hence the distance of separation is 2.87m
Answer:
Potential energy
Explanation:
Before release, the catapult has potential energy stored in a tension of torsion device in it. Normally a flexible bow like object that could be made of wood or of metal.
The answer is C.Mifepristone
The shadow that will be protected on the ground will represent the hawk's horizontal position. therefore it will move at the hawk's horizontal velocity component, which is:
5*cos(60) = 2.5 m/s
Hi there!
Recall that:
Change in momentum = mass × change in velocity
Or:
Δp = mΔv = m(vf - vi)
Plug in the given values. We can assign east to be positive and west to be negative in this instance (Velocity is a vector with direction).
Thus:
Δp = (1)(-21 - 10) = -31 kgm/s OR 31 kgm/s WEST.
The correct answer is B.
Change in momentum is EQUIVALENT to the quantity of IMPULSE.
The correct answer is H.
