True
The half-life isn’t applicable to a first order reaction because it does not rely on the concentration of reactant present. However the 2nd order reaction is dependent on the concentration of the reactant present.
The relationship between the half life and the reactant is an inverse one.
The half life is usually reduced or shortened with an increase in the concentration and vice versa.
Due to attraction ... of opposite charges
I think it’s b... not sure tho sorry
Answer: 11%
Explanation:
Given that
X = ab^2/C. Calculate percentage error in X, when percentage error in a,b,c are 4,2 and 3 respectively.
Percentage error of b = 2%
Percentage error of b^2 = 2 × 2 = 4
When you are calculating for percentage error that involves multiplication and division, you will always add up the percentage error values.
Percentage error of X will be;
Percentage error of a + percentage error of b^2 + percentage error of c
Substitute for all these values
4 + 4 + 3 = 11%
Therefore, percentage error of X is 11%
Answer:
0.43
Explanation:
Sum of forces in the y direction:
∑F = ma
N − mg = 0
N = mg
There are friction forces in two directions: centripetal and tangential. The centripetal acceleration is:
ac = v² / r
ac = (35 m/s)² / 564 m
ac = 2.17 m/s²
The total acceleration is:
a = √(ac² + at²)
a = √((2.17 m/s²)² + (3.62 m/s²)²)
a = 4.22 m/s²
Sum of forces:
∑F = ma
Nμ = ma
mgμ = ma
μ = a / g
μ = 4.22 m/s² / 9.8 m/s²
μ = 0.43
