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Bad White [126]

3 years ago

7

What is not as soft as it's name implies in Anthropology forensic sciences?

1 answer:

irakobra [83]3 years ago

5 0

No baby you baby no se que no se le da la gana de que se vaya de vacaciones yes because

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The gravitational strength at the poles is greater than the gravitational strength at the equator. What will happen to an object

geniusboy [140]

Answer:

C

Explanation:

Because this same question was on my test last week and I got it correct

3 0

3 years ago

What is kinetic energy of 6 kg bowling ball if it is going 6.1 m/s

weqwewe [10]

Answer:111.63 joules

Explanation:

Kinetic energy=(massx(velocity)^2)/2

Kinetic energy=(6×(6.1)^2)/2

Kinetic energy=(6×37.21)/2

Kinetic energy=223.26/2

Kinetic energy=111.63 joules

7 0

3 years ago

A toy rocket fires its engines to launch it straight up from rest. After a short time, the engine turns off and the

madreJ [45]

Answer:

at 10 seconds.. b/c that's when the velocity stops increasing..

Explanation:

8 0

3 years ago

A cube 6.0 cm on each side is made of a metal alloy. After you drill a cylindrical hole 2.0 cm in diameter all the way through a

Crank

To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and the geometric relationships that allow us to find the volume of the figures presented.

For the particular case of the Cube with equal sides its volume is determined by

$V_c = l^3$

$V_c = 6^3 = 216cm^3$

In the case of perforated material we have that its volume is given according to the cylindrical geometry, that is to say

$V_d = \pi r^2*l$

$V_d = \pi (\frac{2}{2})^2*6$

$V_d = 6\pi cm^3$

In this way the net volume would be

$\Delta V = V_c-V_d$

$\Delta V = 216cm^3-6\pi cm^3$

$\Delta V = 197.15cm^3 = 197.15*10^{-6}m^3$

We need to find the mass, but we have the Weight and Gravity so from Newton's second Law

$F= mg$

$m = \frac{F}{g}$

$m = \frac{6.6}{9.8}$

$m = 0.673kg$

PART A) From the relation of density as a unit of mass and volume we have to

$\rho = \frac{m}{V}$

$\rho = \frac{0.673}{197.15*10^{-6}}$

$\rho = 3413.64kg/m^3$

PART B) To find the weight of the cube then we apply the ratio of

$W = mg$

$W = V\rho g$

$W = (216*10^{-6})(3413.64)(9.8)$

$W = 7.22N$

3 0

3 years ago

Can you answer my questions. Please help me

earnstyle [38]

Answer:

answered it.................

8 0

3 years ago