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mars1129 [50]
3 years ago
8

A sample of h gas (2.0 l) at 3.5 atm was combined with 1.5 l of n gas at 2.6 atm pressure at a constant temperature of 25c into

a 7.0 l flask. the total pressure in the flask is _____ atm. assume the initial pressure in the flask was 0.00 atm.
Chemistry
1 answer:
nadya68 [22]3 years ago
3 0
For this problem, assume ideal gas then we use the Combined Gas Law.

P₁V₁/T₁ + P₂V₂/T₂ = PV/T
where P, V and T are the total pressure, volume and temperature

Since temperature is kept constant, the equation is simplified to:

P₁V₁ + P₂V₂ = PV
(3.5 atm)(2L) + (2.6 atm)(1.5 L) = (P)(7 L)
Solving for P,
<em>P = 1.56 atm</em>
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Suppose that you take 200 mg of an antibiotic every 8 hr. The​ half-life of the drug is 8 hr​ (the time it takes for half of the
DochEvi [55]

Answer:

600 mg

Explanation:

The initial amount of the drug = 200 mg

The half-life of the drug = 8 hrs

It means that:-

After 6 hours, the concentration becomes :- \frac{200}{2} mg

After 12 hours, the concentration becomes :- \frac{200}{4} mg

After 18 hours, the concentration becomes :- \frac{200}{8} mg

And so on...

Thus,

After infinite time = 200+\frac{200}{2}+\frac{200}{4}+\frac{200}{8}+..

Thus,

After infinite time = 200\times (1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+..)

The sum of the infinite series is:- 1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+.. = \frac{1}{1+\frac{1}{2}}=2

So,

<u>After infinite time = 200\times 2 mg = 600 mg</u>

5 0
4 years ago
Calculate the molality of a 20.0 percent by weight aqueous solution of nh4cl. (molecular weight: nh4cl = 53.5)
cestrela7 [59]
Unfortunately the data provided doesn't include the DENSITY of the ammonium chloride solution and molarity is defined as moles per volume. So without the density, the calculation of the molarity is impossible. But fortunately, there are tables available that do provide the required density and for a 20% solution by weight, the density of the solution is 1.057 g/ml.  
So 1 liter of solution will mass 1057 grams and the mass of ammonium chloride will be 0.2 * 1057 g = 211.4 g. The number of moles will then be 211.4 g / 53.5 g/mol = 3.951401869 mol. Rounding to 3 significant digits gives a molarity of 3.95.  
Now assuming that your teacher wants you to assume that the solution masses 1.00 g/ml, then the mass of ammonium chloride will only be 200g, and that is only (200/53.5) = 3.74 moles.   
So in conclusion, the expected answer is 3.74 M, although the correct answer using missing information is 3.95 M.
8 0
4 years ago
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irina1246 [14]

The answer is A. The vibration caused by the waves through the air eventually weaken, which is why sound diminishes easily over distance.

8 0
3 years ago
In an aqueous solution, 42% of a substance dissociates to release hydronium ions. Which of the following statements is true for
const2013 [10]

Answer: The statement it is a weak acid is true for the substance.

Explanation:

An acid that dissociates completely when dissolved in water to give hydrogen (H^{+}) or hydronium (H_{3}O^{+}) ions is called a strong acid.

For example, HCl is a strong acid.

HCl + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}

An acid that dissociates partially or weakly when dissolved in water to given hydrogen or hydronium ions is called a weak acid.

For example, CH_{3}COOH is a weak acid.

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A strong base is a base which when dissolved in water then it dissociates completely to give hydroxide ions.

For example, NaOH is a strong acid.

A weak base is a base which when dissolved in water then it dissociates partially or weakly to give hydroxide ions.

For example, NH_{3} is a weak base.

Hence, in an aqueous solution where 42% of a substance dissociates to release hydronium ions shows that the dissociation is less than 50%. This means that substance is dissociating weakly so, it is a weak acid.

Thus, we can conclude that the statement it is a weak acid is true for the substance.

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Answer:

A boiling chip, boiling stone, porous bit or anti-bumping granule is a tiny, unevenly shaped piece of substance added to liquids to make them boil more calmly.

These help in making the liquid boil more easily

8 0
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