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Murljashka [212]
3 years ago
14

It is desired to make 1.00 liter of 6.00 M nitric acid from concentrated 16.00 M HNO3.A) How many moles of nitric acid are in 1.

00 L of 6.00 M nitric acid?B) What volume of concentrated 16.00 M nitric acid will contain this number of moles?C) If this volume of concentrated nitric acid (answer to b) is diluted to 1.00 liter, what will be the molarity of the solution?
Chemistry
1 answer:
natima [27]3 years ago
5 0

Answer:

A) 6.00 mol.

B) 0.375 L or 375 mL

C) 6.00 M

Explanation:

Hello,

A) In this case, from the definition of molarity, we compute the moles for the given volume and concentration:

n=M*V=1.00L*6.00mol/L=6.00mol

B) In this case, from the stock solution, the required volume is:

V=\frac{6.00mol}{16.00mol/L}=0.375L

C) In this case, we apply the following formula for dilution process:

M_1V_1=M_2V_2

Thus, solving for the final molarity, we obtain:

M_2=\frac{M_1V_1}{V_2}=\frac{16.00M*0.375L}{1.00L}\\  \\M_2=6.00M

Regards.

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Answer:

Explanation:

The lewis structure (indicating all the atoms and patterns provided as hint in the question) of glycine can be seen in the attachment below. While the chemical structure of glycine can be seen below

         H

          |

H₂N - C - C =O

          |      \

         H      OH

The structure (of glycine) above provides a "fair idea" of how the lewis structure will be.

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3 years ago
The basic principle in balancing a chemical equation is to ______. View Available Hint(s) The basic principle in balancing a che
OlgaM077 [116]

Answer:

have the same number of atoms of each element in the reactants and in the products

Explanation:

<em>The basic principle in balancing a chemical equation would simply be to have the same number of atoms of each element in the reactants and in the products.</em>

<u>A balanced chemical equation is one that has the same number of atoms of each element on the reactant and the product's side of the equation.</u> For example, consider the equation below:

                     H_2 + O_2 --> H_2O

On the reactant's side, there are 2 atoms of H and O while there are 2 atoms of H and 1 atom of O on the product's side. This is an imbalanced equation. In order for it to be balanced, the number of atoms of H and O on the reactant side must be equal to the number of H and O on the product side as below.

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5 0
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Explanation:

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8 0
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Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.
bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr <em>(1)</em>

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = <u><em>181,66 kJ/mol</em></u>

<u><em /></u>

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = <em><u>0,216 kJ/Kmol</u></em>

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ <em>4. +117,1 kJ/mol</em>

<em></em>

I hope it helps!

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3 years ago
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ale4655 [162]
The oxidation is the best thing
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