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lions [1.4K]
3 years ago
8

A 0.0780 kg lemming runs off a

Physics
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

0.913

Explanation:

k.e=1/2mv square

k.e=1/2×0.078g×23.4256m/s square

k.e=0.913J

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Which of these is true of a chemical reaction? (a) energy is always transferred from reactants to products. (b) Energy is transf
lorasvet [3.4K]
The answer is B: energy is transferred, but it can go to the products or the reactants.
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Which of the following is not a natural resource? a. time b. water c. land d. air Please select the best answer from the choices
AleksAgata [21]

Answer: Option (a) is the correct answer.

Explanation:

Resources which are created by human beings are known as man-made resources.

For example, glass, rayon, nylon etc are all man-made resources.

Whereas resources which are naturally created are known as natural resources.

For example, wind, air, water etc are all natural resources.

Thus, we can conclude that out of the given options time is not a natural resource.

3 0
3 years ago
Middle School Physics 5+3 pts
Murljashka [212]
A) The ball on the small ball is far smaller than the force on the basketball.

B) The total momentum before and after the collision remains constant.

C) We know momentum is conserved so we do:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.1 x 5 + 0.6 x 0 = 0.1 x -4 + 0.6 x v₂
v₂ = 1.5 m/s
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Randy observed that cooked onions in his food taste very differently from the raw onions that he had on his salad. He wondered w
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It's called a hypothesis :D
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4 years ago
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Calculate the entropy change that occurs when 1.0kg of water at 20.00 C is mixed with 2.0kg of water at 80.00 C
SOVA2 [1]

Answer:

The change in entropy ΔS = 0.0011 kJ/(kg·K)

Explanation:

The given information are;

The mass of water at 20.0°C = 1.0 kg

The mass of water at 80.0°C = 2.0 kg

The heat content per kg of each of the mass of water is given as follows;

The heat content of the mass of water at 20.0°C = h₁ = 83.92 KJ/kg

The heat content of the mass of water at 80.0°C = h₂ = 334.949 KJ/kg

Therefore, the total heat of the the two bodies = 83.92 + 2*334.949 = 753.818 kJ/kg

The heat energy of the mixture =

1 × 4200 × (T - 20) = 2 × 4200 × (80 - T)

∴ T = 60°C

The heat content, of the water at 60° = 251.154 kJ/kg

Therefore, the heat content of water in the 3 kg of the mixture = 3 × 251.154 = 753.462

The change in entropy ΔS = ΔH/T = (753.818 - 753.462)/(60 + 273.15) = 0.0011 kJ/(kg·K).

8 0
3 years ago
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