Answer:
- The equivalent capacitance of the combination is greater than the capacitance of either of the capacitors.
- The voltage across each of the capacitors is the same.
- The sum of the charge stored on each capacitor is equal to the charge supplied by the battery.
Explanation:
The capacitance connected in parallel will have the same potentials across its ends. If the battery has a charge Q, it is divided among the capacitors.
That is,
Q = q₁ + q₂ + q₃
But, the potential is shared equally as V. So, the individual capacitance of the equation has the form q₁ = C₁V , q₂ = C₂V, etc.
So, in this case, when the effective capacitance is formulated, it would be
C = C₁ + C₂ + C₃ farad
Therefore, the true statements are
The equivalent capacitance of the combination is greater than the capacitance of either of the capacitors.
The potential across each of the capacitors is the same.
The charge supplied by the battery divided among the capacitors.
Answer:
I₃/Io % = 0.8.59
Explanation:
A polarizer is a complaint sheet for light in the polarization direction and blocks the perpendicular one. When we use two polarizers the transmission between them is described by Malus's law
I = I₀ cos² θ
Let's apply the previous exposures in our case, the light is indicatively not polarized, so the first polarized lets half of the light pass
I₁ = ½ I₀
The light transmitted by the second polarizer
I₂ = I₁ cos² θ
I₂ = (½ I₀) cos2 28
The transmission by the polarizing third is
I₃ = I₂ cos² θ₃
The angle of the third polarizer with respect to the second is
θ₃ = 90-28
θ₃ = 62º
I₃ = (½ I₀ cos² 28 cos² 62)
Let's calculate
I₃ = Io ½ 0.7796 0.2204
I₃ = Io 0.0859
I₃/Io= 0.0859 100
I₃/Io % = 0.8.59
Consider the motion towards right as positive and motion towards left as negative.
m₁ = mass of the cart moving to right = 0.500 kg
v₁ = initial velocity before collision of the cart moving towards right = 2.2 m/s
m₂ = mass of cart moving to left = 0.800 kg
v₂ = initial velocity before collision of the cart moving towards left = - 1.1 m/s
initial momentum of the system of carts before the collision is given as
P₁ = m₁ v₁ + m₂ v₂
P₁ = (0.500) (2.2) + (0.800) (- 1.1)
P₁ = 0.22 kg m/s
P₂ = momentum of system of carts after collision
As per conservation of momentum,
Momentum of system of carts after collision = Momentum of system of carts before collision
P₂ = P₁
P₂ = 0.22 kg m/s
The distance travelled by the car after the first four hours of the trip is 370 km and the average speed for the first four hours of the trip is 92.5 kmph
v ( t ) = d ( t ) / t
v ( t ) = Velocity with respect to time
d ( t ) = Distance with respect to time
t = Time
For the first four hours, the following details are taken from the graph shown.
d ( 4 ) = 370 km
t = 4 hr
v ( 4 ) = 370 / 4
v ( 4 ) = 92.5 kmph
Average velocity can also be calculated using the formula V = ( u + v ) / 2 if the initial and final velocities are given. u represents initial velocity and v represents the final velocity.
Therefore,
Distance travelled in first 4 hours = 370 km
Average speed in first four hours = 92.5 kmph
To know more about average velocity
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Answer:
Van der Waal's equation
Explanation:
The Van der Waal's equation is use to calculate the properties of a gas under nonideal or real gases conditions.
.
Here P, V ,T ,n and R have usual meaning as in the ideal gas equation
that is PV=nRT
with the difference of constant a and b. a and b are constants representing magnitude of intermolecular attraction and excluded volume respectively respectively.