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Bad White [126]
2 years ago
14

a hiker walks 11km due north from camp and then turns and walks 11 km due east. What is the approximate displacement of the hike

r from the camp?
Physics
1 answer:
PIT_PIT [208]2 years ago
3 0

Answer:

d=11\sqrt2\ km

Explanation:

Given that,

Displacement in North = 11 km

Displacement in East = 11 km

We need to find the approximate displacement of the hiker from the camp. It can be calculated by resultant of two displacement as follows :

d=\sqrt{11^2+11^2}\\\\= 11\sqrt2\ km

Hence, the approximate displacement of the hiker from the camp is 11\sqrt2\ km.

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Answer:

1.4m/s

Explanation:

Average velocity is the total distance covered divided by the total time taken.

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The first distance covered  = velocity x time  = 1.4 x 5 = 7m

     second distance covered  = velocity x time  = 1.4 x 6  = 8.4m

So;

  Average velocity  = \frac{7 + 8.4}{11}    = 1.4m/s

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0.3659

Explanation:

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since both the bulbs radiate same power

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substituting the values in the above question we get

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2 years ago
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