Answer:
a) Rmin ≈ 52 m
b) D = 110.184°
c) Lc ≈ 59 m
d) PT Station = 2827+12.37
PT Station = 2827+78.63
Explanation:
a) Given
v = 70 mph = (70 mph)(1,609 m/1 mile)(1 h/3600 s) = 31.286 m/s
e = 3% = 0.03
f = 0.12
a) We can use the equation
Rmin = v²/(127*(e + f))
⇒ Rmin = (31.286)²/(127*(0.03 + 0.12))
⇒ Rmin = 51.38 m ≈ 52 m
b) We can use the equation
D = 5729.578/R ⇒ D = 5729.578/52
⇒ D = 110.184°
c) We apply the formula
Lc = R*Δ/57.3
If Δ = 65° we have
Lc = 52*65/57.3
⇒ Lc = 58.98 m ≈ 59 m
d) If the PI is station 2827+45.50 we get the tangent length T as follows:
T = R*tan(Δ/2)
⇒ T = 52*tan(65/2) = 33.13 m
then, the station of the PC will be
PC Station = PI - T
⇒ PC Station = (2827+45.50) - (0+33.13) = 2827+12.37
and the station of the PT will be
PT Station = PI + T
⇒ PT Station = (2827+45.50) + (0+33.13) = 2827+78.63
Where is Eq.(28) ?? You should show it to find the result
Answer:
Jordan has more green paints
Explanation:
Given


Required
Which paint does he have more?
For better understanding, it's better to convert both measurements to decimal.
For the green paint:


For the blue paint:


By comparison:

<em>This means that Jordan has more green paints</em>
Answer:
As the ER diagram is to be drawn in some tool so it is attached as snapshot i have taken from my tool.
Explanation:
Please find snapshot below for detailed ER diagram.
Answer:
Velocity of ball B after impact is
and ball A is 
Explanation:
= Initial velocity of ball A

= Initial velocity of ball B = 0
= Final velocity of ball A
= Final velocity of ball B
= Coefficient of restitution = 0.8
From the conservation of momentum along the normal we have

Coefficient of restitution is given by



Adding the above two equations we get



From the conservation of momentum along the plane of contact we have


Velocity of ball B after impact is
and ball A is
.