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3 years ago

11

How am i able to answer this?

1 answer:

ratelena [41]3 years ago

7 0

Whats the question so i can answer

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Which of the following chemical equations represents an oxidation-reduction reaction?

zimovet [89]

C. Represents an oxidation-reduction reaction

7 0

3 years ago

What is a substance?

shusha [124]

I think the answer is C. An element or compound that cannot be physically separated. Sorry if im wrong.

7 0

3 years ago

If you have 10,000 grams of a substance that decays with a half-life of 14 days, then how much will you have after 56 days?

Crank

Answer: 625 grams

Explanation:

14 goes into 56, 4 times.

10,000÷2=5,000 - first half life

5,000÷2=2,500 - second half life

2,500÷2=1,250 - 3rd half life

1,250÷2= 625 - 4th half life

Note: don't type "grams" after 625, just type "625".

5 0

2 years ago

Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid

jasenka [17]

Answer: a) The $K_a$ of acetic acid at $25^0C$ is $1.82\times 10^{-5}$

b) The percent dissociation for the solution is $4.27\times 10^{-3}$

Explanation:

$CH_3COOH\rightarrow CH_3COO^-H^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.10 M and $\alpha$ = ?

Also $pH=-log[H^+]$

$2.87=-log[H^+]$

$[H^+]=1.35\times 10^{-3}M$

$[CH_3COO^-]=1.35\times 10^{-3}M$

$[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M$

Putting in the values we get:

$K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}$

$K_a=1.82\times 10^{-5}$

b) $\alpha=\sqrt\frac{K_a}{c}$

$\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}$

$\alpha=4.27\times 10^{-5}$

$\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}$

5 0

3 years ago

How many cubic feet of air at standard conditions 1.00 atm are required to inflate a bicycle tote of .50 cu. Ft. To a pressure o

Alexeev081 [22]

As I am reading the problem, I see they gave you two pressures, one volume and they are asking for another volume. this should give you a hint that you need to use the following formula.

P1V1= P2V2

P1= 1.00 atm
V1= 0.50 ft³
P2= 3.00 atm
V2= ?

Now we plug the values

(1.00 x 0.50)= (3.00 x V2)

V2= 0.17 ft³

3 0

3 years ago