answer:
i am pretty sure you use cross charges for this.
so i think it is the third choice.
The reaction involved in this problem is called the combustion reaction where a hydrocarbon reacts with oxygen to product carbon dioxide and water. The reaction of C2H5OH would be as follows:
C2H5OH + 3O2 = 2CO2 + 3H2O
To determine the number of molecules of CO2 that is formed, we need to determine the number of moles produced from the initial amount of C2H5OH and the relation from the reaction. Then we multiply avogadros number which is equal to 6.022x10^23 molecules per mole.
2.00 g C2H5OH ( 1 mol C2H5OH / 46.08 g C2H5OH ) ( 2 mol CO2 / 1 mol C2H5OH ) = 0.0868 mol CO2
0.0868 mol CO2 ( 6.022x10^23 molecules / mol ) = 5.23x10^22 molecules CO2
this is due to the difference in electron density. Butylamine has more electron density than ammonia. Due to this reason is a Butylamine stronger base than ammonia. BUtylamine has positive induction effect of -CH3 group electron density on N atom which increases
Answer:
4.18 kJ / 6.55x10-3 mol = 638.6 kJ/mol = experimental ΔHC kJ/mol methanol.
Explanation:
