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enot [183]
3 years ago
14

Nitrogen,oxygen and argon are obtained from liquid air by fractional distillation.State the physical property that makes this po

ssible​
Chemistry
1 answer:
Maurinko [17]3 years ago
8 0

they have different boiling points

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How many moles of Al will be consumed when 0.400 mol of Al2O3 are produced in
Vladimir [108]

Answer:

C) 0.800 mol

Explanation:

  • 4Al + 3O₂ → 2Al₂O₃

In order to <u>convert from moles of Al₂O₃ into moles of Al</u>, we'll need to use<em> the stoichiometric coefficients</em>, using a conversion factor that has Al₂O₃ moles in the denominator and Al moles in the numerator:

  • 0.400 mol Al₂O₃ * \frac{4molAl}{2molAl_2O_3} = 0.800 mol Al

So the correct answer is option C).

7 0
3 years ago
Two major discoveries of the gold foil experiment
tiny-mole [99]
Rutherford's gold foil experiment proved that there was a small, dense, positively charged nucleus at the center, which contained most of the mass of the atom. Which contained electrons orbiting the nucleus.
5 0
3 years ago
8. What is probability?​
nata0808 [166]

Answer:

<em>In equipment reliability, the likelihood that a given event will occur</em>

Explanation:

6 0
3 years ago
2. Hydrogen gas at a temperature of 22.0°C that is confined in a 5.00L cylinder exerts a pressure of 4.20atm. If the gas is rele
Umnica [9.8K]

Answer: n∗R=22+273.15/4.2∗5n

P2=n∗R∗T2/V2=n∗R∗33.6+273.15/10

Explanation:

4 0
3 years ago
1. Marisa determined the melting point of a substance to be 24.5C. Find the percent error of her measurement if the actual melti
USPshnik [31]

Answer:

\%\ Error = 21.5\%

Explanation:

Given

Measured = 24.5

Actual = 31.2

Required

Determine the percentage error

First, we need to determine the difference in the measurement

Difference = |Actual - Measured|

Difference = |31.2 - 24.5|

Difference = |6.7|

Difference = 6.7

The percentage error is calculated as thus:

\%\ Error = \frac{Difference * 100\%}{Actual}

\%\ Error = \frac{6.7 * 100\%}{31.2}

\%\ Error = \frac{670\%}{31.2}

\%\ Error = 21.4743589744\%

\%\ Error = 21.5\% <em>approximated</em>

6 0
3 years ago
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