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snow_tiger [21]
3 years ago
8

which weapons did germany used when they had war with Ussr? and which weapons did Ussr used during the war?​

Chemistry
1 answer:
MrRissso [65]3 years ago
8 0

Answer: submachine guns

Explanation:first And for most German soldiers took Soviet SSH 39 in ssh40 helmet from Fallen Russians. They were considerably heavier than German models, but provided better Better protection against shrapnel and ammunition from submachine guns, which were widely used by both sides in the war.

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What is the density of a gas with a molar mass of 28.26 grams per mole at 3.510 ATM in 237 Kelvin​
Vikki [24]
<h3><u>Answer;</u></h3>

= 5.1 g/L

<h3><u>Explanation;</u></h3>

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Number of moles is 1 since one mole has a mass equivalent to the molar mass.

Therefore; We can find the volume and thus get the density.

<em>V = nRT/P</em>

<em>    = (1 × 0.08206 × 237)/3.510</em>

<em>     = 5.5408 L</em>

<em>Hence; Density = mass/volume </em>

<em>                           = 28.26 g/5.5408 L</em>

<em>                           = 5.1 g/L</em>

<em>The Density is 5.1 g/L or 0.005 g/cm³</em>

6 0
3 years ago
WHAT IS THE MASS OF AN OBJECT WHOSE<br> DENSITY IS 0.23 G/ML AND A VOLUME OF<br> 22.5 ML?
7nadin3 [17]

Answer:

<h2>The answer is 5.18 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 22.5 mL

density = 0.23 g/mL

We have

mass = 0.23 × 22.5 = 5.175

We have the final answer as

<h3>5.18 g</h3>

Hope this helps you

4 0
3 years ago
Describe how hibernation has helped bear species survive.
Ivenika [448]
In the winter bears hibernate because food is scarce during the winter, and it is also very cold. During hibernation a bears body temperature drops, and they do not go to the bathroom. This helps them preserve energy as they sleep throughout the winter. Which is what keeps them alive. Hope I could help!!:-)))
5 0
3 years ago
Read 2 more answers
. What is the molarity of a solution in which 6.50 mol of NaOH is dissolved in
netineya [11]

Answer:

For 6.50 mol NaOH -  1.44M.

For 6.50 g NaOH - C. 0.0361 M

Explanation:

For 6.50 mol NaOH.

Molarity = moles solute/L solution = 6.5 mol/4.5 L solution = 1.44 mol/L=1.44M

There is no such answer in given choices.

For 6.50 g NaOH

M(NaOH) = 23 + 16 + 1 = 40 g/mol

Molarity = 6.5g* 1 mol/40g *1/4.5L = 0.0361 mol/L = 0.0361 M

There is such answer. It is C.

4 0
3 years ago
How many chemical reactions are possible regarding the formation of carbonic acid and the dissolving of calcite?
Jlenok [28]
Chemical reactions that are possible regarding the formation of the carbonic acid and the dissolving of calcite are 3.

So, the best option is A. 3.
3 0
3 years ago
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