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snow_tiger [21]
3 years ago
8

which weapons did germany used when they had war with Ussr? and which weapons did Ussr used during the war?​

Chemistry
1 answer:
MrRissso [65]3 years ago
8 0

Answer: submachine guns

Explanation:first And for most German soldiers took Soviet SSH 39 in ssh40 helmet from Fallen Russians. They were considerably heavier than German models, but provided better Better protection against shrapnel and ammunition from submachine guns, which were widely used by both sides in the war.

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24 g of magnesium were burned in oxygen. The compound formed had a mass of 40 g. Explain why the mass had gone up.
DIA [1.3K]

Answer :

According to the law of conservation of mass, the mass of reactants must be equal to the mass of products.

The balanced chemical reaction is,

Mg+\frac{1}{2}O_2\rightarrow MgO

As we know that the molar mass of magnesium is 24 g/mole, the molar mass of O_2 is 32 g/mole and the molar mass of magnesium oxide is 40 g/mole.

From the given balanced reaction, we conclude that

As, 1 mole of magnesium react \frac{1}{2} mole of oxygen to give 1 mole of magnesium oxide.

So, the mass of Mg is 24 g, the mass of O_2=\frac{1}{2}\times 32=16g and the mass of MgO is 40 g.

That means 24 g of Mg react with 16 g O_2 to give 40 g of MgO.

8 0
3 years ago
How many molecules of zinc oxide are there in a 2 kg sample?
Novosadov [1.4K]

There are 1.48 × 10²⁵ molecules of zinc oxide in a 2 kg sample. Details about number of molecules can be found below.

<h3>How to calculate number of molecules?</h3>

The number of molecules of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

According to this question, there are 2000g of ZnO in a sample. Zinc oxide has a molar mass of 81.38 g/mol.

no of moles = 2000g ÷ 81.38g/mol

no of moles = 24.57mol

number of molecules = 24.57 × 6.02 × 10²³

number of molecules = 147.95 × 10²³

Therefore, there are 1.48 × 10²⁵ molecules of zinc oxide in a 2 kg sample.

Learn more about number of molecules at: brainly.com/question/11815186

#SPJ1

6 0
2 years ago
In the titration of wine to determine the acid concentration, 10.0 mL of wine was placed in a beaker and diluted with 40.0 mL of
BARSIC [14]

Answer:

0.0042 M is the molarity of tartaric acid in this sample of wine.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is tartaric acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=10.0+40.0 mL=50.0 mL\\n_2=1\\M_2=0.051 M M\\V_2=8.20 mL

Putting values in above equation, we get:

2\times M_1\times 50.0 mL=1\times 0.051 M\times 8.20 mL

M_1=\frac{1\times 0.051 M\times 8.20 mL}{2\times 50.0 mL}=0.0042 M

0.0042 M is the molarity of tartaric acid in this sample of wine.

6 0
3 years ago
Do blood cells have a rigid of cells walls
KatRina [158]

<em>Yes</em> the blood cells have a rigid of cell walls as their cell walls are cell membrane.

4 0
3 years ago
What is the limiting reactant when 5.6 moles of aluminum react with 6.2 moles of water?
alexira [117]

The limiting  reactant  when 5.6  moles   of aluminium react  with  6.2  moles   of water   is

      water( H2O)


      <u><em>Explanation</em></u>

The  balanced    equation is as below

2 Al +3 H2O  →  Al2O3  +3 H2

The mole ratio  of Al :Al2O3  is 2:1  therefore  the  moles  of  Al2O3

  = 5.6 x1/2  =  2.8  moles


The   mole  ratio  of H2O: Al2O3  is 3:1 therefore  the  moles  of Al2O3  produced

                 = 6.2  x1/3= 2.067  moles


since  H2O  yield  less  amount  of Al2O3 ,  H2O   is  the limiting reagent.

7 0
3 years ago
Read 2 more answers
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