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3 years ago

5

What is the chemical formula for this?

2 answers:

guajiro [1.7K]3 years ago

5 0

Answer:

-OOH

Explanation:

This forms an acid if it comes in contact with a metal

wariber [46]3 years ago

5 0

Answer:

HO2; Hydroperoxyl

Explanation:

Since there are two oxygen molecules, and one hydrogen molecule, it can be classified as a hydroperoxyl molecule.

It is an inorganic compound with the following characteristics

Covalent compound (O,H are nonmetals)
Valence of O (O must form an octet): 6
Valence of H: 1
Total valence electrons: 13
Molar mass: 33.01 g/mol

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For each row in the table below, decide whether the pair of elements will form a molecular or ionic compound. If they will, then

Olin [163]

Answer:

$\begin{array}{cccll}\textbf{Element 1} & \textbf{ Element 2} &\textbf{Compound?} &\textbf{Formula} &\textbf{Type}\\\text{Ar}&\text{Xe} &\text{No} &\text{None}&\text{Neither}\\\text{F}& \text{Cs} &\text{Yes} &\text{CsF} &\text{Ionic}\\\text{N} &\text{Br} &\text{Yes} & \text{NBr}_{3}&\text{molecular} \\\end{array}$

Explanation:

You look at the type of atom and their electronegativity difference.

If ΔEN <1.6, covalent; if ΔEN >1.6, ionic

Ar/Xe: Noble gases; no reaction

F/Cs: Non-metal + metal; ΔEN = |3.98 – 0.79| = 3.19; Ionic

N/Br: Two nonmetals; ΔEN = |3.04 - 2.98| = 0.

4 0

3 years ago

How many moles of H20 are needed to produce 1 mole of O2 in the following equation?

Alex787 [66]

2 moles is the answer

6 0

3 years ago

My mom is making SPAGET

Keith_Richards [23]

Answer:

yes

Explanation:

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3 years ago

How many grams of solute are needed to order to prepare 100.00 mL of a 0.1000 M solution of a compound with a molecular weight o

Troyanec [42]

The grams of solute are required.

The mass of solute is 3.5 g

c = Molarity = 0.1 M

M = Molar mass = 350 g/mol

V = Volume of solution = 100 mL = 0.1 L

n = Number of moles

m = Mass of solute

Molarity is given by

$c=\dfrac{n}{V}\\\Rightarrow n=cV\\\Rightarrow n=0.1\times 0.1\\\Rightarrow n=0.01\ \text{moles}$

Molar mass is given by

$M=\dfrac{m}{n}\\\Rightarrow m=Mn\\\Rightarrow m=350\times 0.01\\\Rightarrow m=3.5\ \text{g}$

The mass of solute is 3.5 g

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Otrada [13]

Answer:

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Explanation:

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