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3 years ago

Characteristics of bipolar disorder typically include

Chemistry

2 answers:

crimeas [40]3 years ago

7 0

The correct answer is option b, that is, difficulty concentrating.

Manic depression also called bipolar disorder refers to a mental disorder, which leads to periods of unusually elevated mood and the periods of depression. The elevated mood is substantial and is called hypomania or mania, on the basis of its severity, or whether the signs of psychosis are there.

One of the usual sign of bipolar disorder is the difficulty in concentrating or diminished the tendency to think and indecisiveness. The individual suffering with the condition seems to make wrong decisions due to this sign, and as they do not think completely, the patients suffering from bipolar disorder possess poor decision making.

I am Lyosha [343]3 years ago

3 0

C. Difficulty in concentrating.
One of the common symptom for Bipolar disorder is the difficulty in concentration or decreased ability to think and indecisiveness. They tend to make wrong decisions because of this symptom. And because they do not think thoroughly, bipolar disorder patients have poor decision making.

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What was the robotic vehicle Opportunity designed to do?

mestny [16]

I believe the answer is C

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4 years ago

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Seawater has a ph of 8.1. what is the concentration of oh–?

lara31 [8.8K]

PH scale is used to determine how acidic or basic a solution is.
pH can be calculated as follows;
by knowing the ph we can calculate pOH
pH + pOH = 14
pOH = 14 - 8.1
pOH = 5.9
pOH is used to calculate the hydroxide ion concentration
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 1.26 x 10⁻⁶ M
therefore hydroxide ion concentration is 1.26 x 10⁻⁶ M

4 0

3 years ago

If 1000. mL of water freezes, which of the following is a reasonable approximation for the volume of the resulting ice?

Fudgin [204]

Answer:

If 1000. mL of water freezes, which of the following is a reasonable approximation for the volume of the resulting ice?

Group of answer choices

1000. mL

961 mL

1040 mL

Explanation:

Ice is fewer denser than water.

The reason is the volume occupied by the same mass of ice with water is more than the volume occupied by water. Ice has more empty space within it.

Due to this reason, ice floats on water.

When 1000ml of water freezes to ice then its volume is greater than water.

Among the given options the correct answer is 1040 mL .

7 0

3 years ago

Tetrahydrofuran (THF) is a common organic solvent with a boiling point of 339 K. Calculate the total energy (q) required to conv

poizon [28]

Explanation:

For the given reaction, the temperature of liquid will rise from 298 K to 339 K. Hence, heat energy required will be calculated as follows.

$Q_{1} = mC_{1} \Delta T_{1}$

Putting the given values into the above equation as follows.

$Q_{1} = mC_{1} \Delta T_{1}$

= $27.3 g \times 1.70 J/g K \times 41$

= 1902.81 J

Now, conversion of liquid to vapor at the boiling point (339 K) is calculated as follows.

$Q_{2}$ = energy required = $mL_{v}$

$L_{v}$ = latent heat of vaporization

Therefor, calculate the value of energy required as follows.

$Q_{2}$ = $mL_{v}$

= $27.3 \times 444$

= 12121.2 J

Therefore, rise in temperature of vapor from 339 K to 373 K is calculated as follows.

$Q_{3} = mC_{2} \Delta T_{2}$

Value of $C_{2}$ = 1.06 J/g, $\Delta T_{2}$ = (373 -339) K = 34 K

Hence, putting the given values into the above formula as follows.

$Q_{3} = mC_{2} \Delta T_{2}$

= $27.3 g \times 1.06 J/g \times 34 K$

= 983.892 J

Therefore, net heat required will be calculated as follows.

Q = $Q_{1} + Q_{2} + Q_{3}$

= 1902.81 J + 12121.2 J + 983.892 J

= 15007.902 J

Thus, we can conclude that total energy (q) required to convert 27.3 g of THF at 298 K to a vapor at 373 K is 15007.902 J.

5 0

3 years ago

The density of air under ordinary conditions at 25°C is 1.19 g/L. How many kilograms of air are in a room that measures 10.0 ft

Lunna [17]

Answer: The mass of air present in the room is 37.068 kg

Explanation : Given,

Length of the room = 10.0 ft

Breadth of the room = 11.0 ft

Height of the room = 10.0 ft

To calculate the volume of the room by using the formula of volume of cuboid, we use the equation:

$V=lbh$

where,

V = volume of the room

l = length of the room

b = breadth of the room

h = height of of the room

Putting values in above equation, we get:

$V=10.0ft\times 11.0ft\times 10.0ft=1100ft^3=31148.53L$

Conversion used : $1ft^3=28.3168L$

Now we have to calculate the mass of air in the room.

$Density=\frac{Mass}{Volume}$

$1.19g/L=\frac{Mass}{31148.53L}$

$Mass=37066.7507g=37.068kg$

Conversion used : (1 kg = 1000 g)

Therefore, the mass of air present in the room is 37.068 kg

3 0

3 years ago

Read 2 more answers