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3 years ago

Characteristics of bipolar disorder typically include

Chemistry

2 answers:

crimeas [40]3 years ago

7 0

The correct answer is option b, that is, difficulty concentrating.

Manic depression also called bipolar disorder refers to a mental disorder, which leads to periods of unusually elevated mood and the periods of depression. The elevated mood is substantial and is called hypomania or mania, on the basis of its severity, or whether the signs of psychosis are there.

One of the usual sign of bipolar disorder is the difficulty in concentrating or diminished the tendency to think and indecisiveness. The individual suffering with the condition seems to make wrong decisions due to this sign, and as they do not think completely, the patients suffering from bipolar disorder possess poor decision making.

I am Lyosha [343]3 years ago

3 0

C. Difficulty in concentrating.
One of the common symptom for Bipolar disorder is the difficulty in concentration or decreased ability to think and indecisiveness. They tend to make wrong decisions because of this symptom. And because they do not think thoroughly, bipolar disorder patients have poor decision making.

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Neon is compressed from 100 kPa and 16°C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and

Viktor [21]

Answer:

$\Delta v=-0.952m^3/kg$

$\Delta h=0$

Explanation:

In this case, since neon could be considered as an ideal gas, the specific volumes at the first and second state are respectively:

$v_1=\frac{Rg*T_1}{p_1}=\frac{0.4119kJ/kg*K*289.15}{100kPa} =1.19m^3/kg\\$

$v_2=\frac{Rg*T_2}{p_2}=\frac{0.4119kJ/kg*K*289.15}{500kPa} =0.238m^3/kg\\$

Thus, the change in the specific volume turns out:

$\Delta v=v_2-v_1=0.238m^3/kg-1.19m^3/kg\\\Delta v=-0.952m^3/kg$

Which value has sense for the compression.

In addition, the specific enthalpy change just depend on the temperature as it is an ideal gas, therefore, since the process es isothermic:

$\Delta h=Cp\Delta T=0$

Best regards.

3 0

4 years ago

Hydrogen sulfide gas gives rotten eggs their terrible odor. Hydrogen sulfide burns in air (O2) to produce sulfide dioxide gas an

gizmo_the_mogwai [7]

Answer:

2.07 mol O₂

Explanation:

First we need to write down the species present in the chemical equation, using the information given by the exercise:

H₂S + O₂ → SO₂ + H₂O

However this equation is not balanced, so now we balance it:

2H₂S + 3O₂ → 2SO₂ + 2H₂O

Now we can use the stoichiometric ratio to calculate the moles of oxygen from the moles of sulfide dioxide:

1.38 molSO₂ * $\frac{3molO_{2}}{2molSO_{2}}$ = 2.07 mol O₂

8 0

3 years ago

What class of the periodic table is made up of elements that readily give off electrons in a chemical reaction?

leonid [27]

Answer:

hope this helpful

Explanation:

Non metalls

6 0

3 years ago

In a solution, the substance that has been dissolved is called the...

amm1812

Answer:

solute

Explanation:

The substance being dissolved is called a solute. The thing the solute is being dissolved in is called a solvent.

6 0

3 years ago

Read 2 more answers

Part a cyclohexane has a freezing point of 6.50 ∘c and a kf of 20.0 ∘c/m. What is the freezing point of a solution made by disso

Andrei [34K]

The mathematical expression for the depression in freezing point is given as:

$\Delta T_{f}= k_{f}m$

where, $\Delta T_{f}$ = depression in freezing point

$k_{f}$ = molal depression constant (20.0 $^{o}Ckg/mole$ )

m = molality

Molality is defined as the ratio of number of moles of solute to the kg of the solvent

Number of moles = $\frac{given mass in g}{molar mass}$

given mass of biphenyl solute = 0.925 g

Molar mass of biphenyl = 154.21 g/mol

Put the values,

number of moles of biphenyl = $\frac{0.925 g}{154.21 g/mol}$

= $0.0059 mole$

Molality = $\frac{number of moles of biphenyl solute}{mass of the solvent in kg}$

Mass of cyclohexane solvent = 25.0 g

Convert g into kg: 1 kg = 1000 g

Thus, mass of cyclohexane = $\frac{25.0}{1000}$

= 0.025 kg

Now, put the values in the formula of molality:

Molality = $\frac{0.0059 mole}{0.025 kg}$

= 0.236 mole/kg or 0.236 m.

Calculate the depression in freezing point:

$\Delta T_{f}= 20.0^{o}C kg/mole\times 0.236 mole/kg$

= $4.72 ^{o}C$

Now, $\Delta T_{f} = T_{solvent} - T_{solution}$

$4.72 ^{o}C = 6.50^{o}C - T_{solution}$

$T_{solution} = 6.50^{o}C- 4.72 ^{o}C$

= $1.78^{o}C$

Hence, freezing point of the solution is $1.78^{o}C$ .

4 0

3 years ago

Read 2 more answers