The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.
<h3>How to calculate the final velocity a moving object?</h3>
From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.
It is expressed as;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
- Initial velocity u = 6m/s
- Acceleration a = 85m/s²
- Elapsed time t = 5s
- Final velocity v = ?
Plug the given values into the first equation of motion and solve for v.
v = u + at
v = 6m/s + ( 85m/s² × 5s )
v = 6m/s + 425ms/s²
v = 6m/s + 425m/s
v = 431m/s
The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.
Learn more about the first equation of equation here: brainly.com/question/20381052
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We are given
V = 100 V
R = 500 Ω
C = 10^4 F
q(0) = 0
We are asked to find the charge q(t) of the RC capacitor.
To solve this, we use the formula:
q(t) = CV [1 - e^(-t/RC) ]
Substituting thet given values
q(t) = 10^4 (100) [1 - e^(-t/500(10^4) ]
q(t) = 1 x 20^6 [1 - e^(-2x10^7 t) ]
Since we only asked to get the charge q(t) in terms of t, the answer is
q(t) = 1 x 20^6 [1 - e^(-2x10^7 t) ]
Answer
Force between two charged bodies q₁ and q₂ is given by the formula below.
F = Kq₁q₂/r²
Where k = constant
r = distance between them
F = (9.0 E9 × 1.0 E-6 × 1.0 E-6)/0.30²
= 9.0E-3/0.30²
= 9.0E-3/0.09
= 0.1 N
3. An object will float if its density is less than the matter it is submerged in.
If it sinks in water, its density is more than 1. If it floats in glycerin, its density is less than 1.26.
Answer:
W= 1812.6 J
Explanation:
Work (W) is defined as the scalar product of force F by the distance (d) the body travels due to this force.
W= F*d* cosα Formula ( 1)
Where:
F is the force in Newtons (N)
d is the displacemente in meters (m)
α : Angle formed between force and displacement
Data
F = 10 N
d = 200 m
α = 25°
Work done by the pulling force while the passenger walks 200 m
We replace data in the formula (1)
W= F*d* cosα
W= (10 N)*(200 m)* cos25°
W= 1812.6 (N*m)
W= 1812.6 J