I eat dicks and and I also masturbate
Answer:
0.44m/s
Explanation:
drift velocity=I/nAq
diameter 12 gauge
wire=0.081inches=0.081*2.5=0.2025cm radius=0.10125cm area=pi*R^2 =20/8.5*10^22*3.14*0.10125^2*10^-4*1.6*10^-19*
V = 0.44m/s
Answer:
2.76×10⁻¹⁰ C
Explanation:
Applying,
V = W/q................... Equation 1
Where V = Electric Potential, E = Electric potential energy, q = charge.
make q the subject of the equation
q = W/V................ Equation 2
From the question,
Given: W = 4.26×10⁻⁸ J, V = 154.5 V
Substitute these values into equation 2
q = 4.26×10⁻⁸/154.5
q = 2.76×10⁻¹⁰ C
Answer:
16.8 seconds
Explanation:
Given that:
Constant speed of rabbit = 4.2 m/s
Initial Velocity (u) of cat = 0
Acceleration (a) of cat = 0.5 m/s²
Time it takes cat to catch rabbit ;
Using the relation:
Distance moved by rabbit (Dr) :
Dr = speed * time ; Dr = 4.2t
Distance moved by Cat (Dc) :
Dc = ut + 0.5at^2
Dc = 0 + 0.5at^2
Hence, Cat will catch rabbit when Dr = Dc
4.2t = 0.5at^2
4.2t = 0.5(0.5)t^2
4.2t = 0.25t^2
Divide both sides by t
4.2 = 0.25t
t = 4.2 / 0.25
t = 16.8 seconds
Hence, the cat will catch the rabbit after 16.8 seconds
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